How to find the point that is equidistant from (5,-5) and (1,1)
1 answer:
Answer:
(3, -2)
Step-by-step explanation:
The <em>midpoint</em> of two points is half-way between the x-values and the y-values.
The formula is
M = ((x₁ + x₂)/2, (y₁ + y₂)/2)
For the points (5,-5) and (1,1),
Half way between the x values is
(x₁ + x₂)/2 = (5 + 1) /2 = 6/2 = 3
Half way between the y values is
(y₁ + y₂)/2= (-5 + 1)/2 = -4/2 = -2
M = (3, -2)
The graph below shows your two points at (5,-5) and (1,1) and the mid-point at (3, -2).
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Answer:
x ≈ 15.9
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
x² + 6² = 17²
x² + 36 = 289 ( subtract 36 from both sides )
x² = 253 ( take the square root of both sides )
x = ≈ 15.9 ( to the nearest tenth )