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BartSMP [9]
3 years ago
14

Express -2x+3y=6 in the form of ax+by+ca and indicate the values of a, b , c ​Please answer

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer:

-2x + 3y = 6

Rearrange

-2x + 3y - 6 = 0

ax + by + ca = 0

a = -2

b = 3

If ca was a typo, and you meant c, then c = -6.

However, if ca wasn't a typo, then:

ca = -6

-2c = -6

c = -6 / -2

c = 3

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30,45,x,100; the mean is 60
Andrei [34K]

if there are 4 numbers that average to 60, when mutiplied they must come up to: 60*4= 240

100+30+45= 175

240-175= 65

PROOF:

100+30+45+65= 240

240÷ 4

= 60

6 0
3 years ago
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The graph of a system of equations with the same slope will have no solutions. (1 point)
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3 years ago
A={ 0,1,3,5,6}; B={1,2,3,7} draw the venn diagram of AUB Writ​
Sati [7]

Answer:

Here,

n(A)={0,1,3,5,6}

n(B)={1,2,3,7}

n(AUB)=?

we know that,

AUB={0,1,2,3,5,6,7}

Step-by-step explanation:

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8 0
2 years ago
For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}

Split the summand into partial fractions:

\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

1=a(1+4)\implies a=\frac15

This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

and as n\to\infty, the second term vanishes and leaves us with

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

7 0
3 years ago
The volume of a cylinder can is 1.54 litre and area of base is 77cm^2 Find its height​
goblinko [34]

Answer:

The height is 20 cm.

Step-by-step explanation:

First, we have to know that the volume formula is V = πr²h and the base area of cylinder is a circle. So we can let πr² be 77 cm² . Then we have to substitute the following values into the formula :

v = 1.54 \: l

v = 1540 \:  {cm}^{3}

v = \pi \times  {r}^{2}  \times h

Let πr² be 77,

Let v be 1540,

1540 = 77 \times h

77h = 1540

h = 1540  \div 77

h = 20 \: cm

5 0
3 years ago
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