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3 years ago

Find the slope of the line passing through the points (1,-5) and (4,1).

1 answer:

4 0

<h3>Answer:</h3><h3>The equation for the slope of a line, given two coordinate points, (x1,y1) , (x2,y2), is (y2-y1)/(x2-x1) </h3><h3> So we get slope = (1-(-5)) / (4-1) = 6/3 = 2</h3><h3>A is your correct answer.</h3>

Hope this helps! please consider marking my answer the brainliest :)

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Name the vertical angles in the diagram below:

SVETLANKA909090 [29]

Hey there!

The vertical angles in the diagram shown are 2 and 3, and 1 and 4, because they are formed by 2 intersecting lines and are across from eachother.

Hope it helps and have a good day!

7 0

3 years ago

A wire 4 1/2 feet long is being cut into smaller pieces of wire, each. 1 1/4 ft long what is the max number of smaller pieces of

ivolga24 [154]

4.5 divided by 1.25 is 3.6

for peices in total it is 4.

for peices the right length it is 3

3 0

3 years ago

Read 2 more answers

PLS HELP WITH THIS QUESTION

alexandr1967 [171]

ANSWER: y=6
straight lines are 180° and all the angles in a triangle add up to 180°

4 0

2 years ago

Read 2 more answers

1. Carter will install fencing all around the flat area of his

MariettaO [177]

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A(3, 6) and B(3, -2) = $\sqrt{(3-3)^2+(6+2)^2}$

= 8 yards

Distance between B(3, -2) and C(-7, 4) = $\sqrt{(3+7)^2+(-2-4)^2}$

= $\sqrt{136}$

= 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = $\sqrt{(-7+7)^2+(4+2)^2}$

= 6 yards

Distance between D(-7, -2) and E(-3, -2) = $\sqrt{(-7+3)^2+(-2+2)^2}$

= 4 yards

Distance between E(-3, -2) and F(-3, -8) = $\sqrt{(-3+3)^2+(-2+8)^2}$

= 6 yards

Distance between F(-3, -8) and G(3, -8) = $\sqrt{(-3-3)^2+(-8+8)^2}$

= 6 yards

Distance between G(3, -8) and H(10, -12) = $\sqrt{(3-10)^2+(-8+12)^2}$

= $\sqrt{49+16}$

= $\sqrt{65}$

= 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = $\sqrt{(10-10)^2+(-12-6)^2}$

= 18 yards

Distance between A(3, 6) and J(10, 6) = $\sqrt{(10-3)^2+(6-6)^2}$

= 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

= 75 yards

Therefore, amount of fencing required = 75 yards

8 0

3 years ago

A spring exerts a force of 6 N when stretched 3 m beyond its natural length. How much work is required to stretch the spring 2 m

lys-0071 [83]

Answer:

4Joules

Step-by-step explanation:

According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

K is the elastic constant

e is the extension

If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'

can be gotten using k = f/e where

F = 6N, e = 3m

K = 6N/3m

K = 2N/m

Work done on an elastic string is calculated using 1/2ke².

If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;

1/2× 2× (2)²

= 4Joules

3 0

3 years ago