In ΔVWX, \text{m}\angle V = (7x-1)^{\circ}m∠V=(7x−1) ∘ , \text{m}\angle W = (4x+16)^{\circ}m∠W=(4x+16) ∘ , and \text{m}\angle X
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Answer: The answer is 381.85 feet.
Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.
This situation is framed very nicely in the attached figure, where
BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?
From the right-angled triangle WGB, we have
and from the right-angled triangle WAB, we have'
Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.
Thus, the height of the building across the street is 381.85 feet.
Answer:
Depreciation fee = $5,850
Step-by-step explanation:
Kindly check attached picture for detailed calculation
