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Lady_Fox [76]
3 years ago
9

I’m so stupid I don’t know

Mathematics
1 answer:
adell [148]3 years ago
4 0

Answer:

I am stupid too, so forgive me if I am wrong.ಥ_ಥ

I am pretty sure the correct answer is D since 2 can be multiplied by 3 to get 6, and 3 can be multiplied by 3 to get 9. Thus, if the number of guitars is multiplied by 3, the number of amps will always be a multiple of 3.

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4 4/10 divided by 4 2/3
leonid [27]

Answer: Responding for points

Step-by-step explanation:

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3 years ago
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Round the following numbers to the nearest 10. The numbers they have is 13,21,29
earnstyle [38]

Answer:

13: 10

21: 20

29: 30

Step-by-step explanation:

5 0
3 years ago
A Ferris wheel is 35 meters in diameter and boarded from a platform that is 3 meters above the ground. The six o'clock position
Umnica [9.8K]

Answer:

height = 20.5068 m    

Step-by-step explanation:

Given the data in the question;

First, lets calculate the amplitude, midline and period of 8minutes

Amplitude = 35 / 2 = 17.5

|A| = 17.5

A = - 17.5  { since the wheel starts at 6 o clock }

midline  C = (35/2) + 3

C = 17.5 + 3

C = 20.5

And period is 8 minutes

⇒ 2π/B = 8

8B = 2π

B = 2π/8 = π/4

So our equation will be in the form of;

y = h(t) = Acos(B×t) + C

∴ h(t) = -17.5cos( π/4×t) + 20.5  

Now, How high are you off the ground after 6 minutes

⇒ height = -17.5cos( π/4 × 6) + 20.5

height = -17.5cos( π/4 × 6) + 20.5    

height = -17.5cos( 4.71238898) + 20.5    

height = -17.5 × cos( 4.712) + 20.5  

height = -17.5 × -0.00038898 + 20.5                  

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8 0
3 years ago
Find the slope of the line that passes through (-20, -51) and (31, -75).
lilavasa [31]

Answer:

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Step-by-step explanation:

m=(y2-y1)/(x2-x1)

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m=(-75+51)/(31+20)

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7 0
3 years ago
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Bas_tet [7]

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Let (x,y,z) be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

\langle x,y,z\rangle - \langle 1,1,-1\rangle = \langle x-1, y-1, z+1 \rangle

and this is perpendicular to \vec n.

So the equation of the plane is

\langle x-1, y-1, z+1 \rangle \cdot \vec n = 0 \implies (x-1) - (y-1) + (z+1) = 0 \implies \boxed{x - y + z = -1}

or equivalently,

\boxed{-x + y - z = 1}

6 0
2 years ago
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