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3 years ago

12

At school, keys are handed out to teachers on rings at the beginning of the year. There are 4 keys on each ring. Make a t-table

that shows the number of keys 3, 4, and 7 rings.

2 answers:

Scorpion4ik [409]3 years ago

4 0

K = 4
3k = 12
4k = 16
7k = 28

zhannawk [14.2K]3 years ago

3 0

K = 4 3k = 12 or 3*4 = 12
4k = 16 or 4*4= 16
7k = 28 or 7*4= 28

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Does anyone get this!??

stepladder [879]

Hello from MrBillDoesMath!

Answer:

8

Discussion:

Let the number be "n". Then the question states that

3n - 15 = (n/2) + 5 => multiply both sides by 2

6n - 30 = n + 10 => subtract n from both sides

5n - 30 = 10 => add 30 to both sides

5n = 30 + 10 = 40 => divide both sides by 5

n = 40/5 = 8

Thank you,

MrB

8 0

2 years ago

When a number is added to 1/5 of itself, the result is 24. The equation that models this problem is n +1/5 n = 24. What is the v

Lady_Fox [76]

For this case we must find the value of n of the following equation:

$n + \frac {1} {5} n = 24$

Taking common factor "n" from the left side of the equation we have:

$n (1+ \frac {1} {5}) = 24\\n \frac {6} {5} = 24$

Multiplying by 5 on both sides of the equation:

$6n = 120$

Dividing between 6 on both sides of the equation:

$n = 20$

Thus, the value of n is 20.

Answer:

$n = 20$

7 0

3 years ago

Read 2 more answers

Mark the points A(5, 5) and B(7.2). Draw a circle that has point A as the center and passes through point B. Measure and label t

olasank [31]

Answer:

i think 4 units im not sure though though

Step-by-step explanation:

4 0

3 years ago

Representatives from the student councils at three area high schools are traveling to the national convention in New York. North

ivann1987 [24]

nshs = sshs+5

wshs = nshh + 6 = sshs + 11

So nshs + wshs + sshs = 3*sshs + 16

So sshs = 10, nshs = 15 and wshs = 21

Answer 15.

8 0

3 years ago

Read 2 more answers

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

lubasha [3.4K]

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

$A(n) = - 6 + (n - 1)( \frac{1}{5} )$

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

$A(1) = - 6 + (1 - 1)( \frac{1}{5} )$

$= - 6 + (0)( \frac{1}{5} )$

$= - 6$

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

$A(4) = - 6 + (4 - 1)( \frac{1}{5} )$

$= - 6 + (3)( \frac{1}{5} )$

$= - 5 \frac{2}{5}$

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

$A(10) = - 6 + (10 - 1)( \frac{1}{5} )$

$= - 6 + (9)( \frac{1}{5} )$

$= - 4 \frac{1}{5}$

Hope this helps you

4 0

2 years ago