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3 years ago

Find the product: (n-5)(n-1)

Mathematics

1 answer:

hjlf3 years ago

7 0

Answer:

6n=5

Step-by-step explanation:

hope it helps tell me how you do

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A dilation with a scale factor of 3. 5 and centered at the origin is applied to PQ¯¯¯¯¯ with endpoints P(2, 5) and Q(2, 1)

velikii [3]

Answer: The answer is P'(7, 17.5) and Q'(7, 3.5).

Step-by-step explanation: Given that a line segment PQ is dilated with a scale factor of 3.5 where origin is the centre of dilation.

The end points of segment PQ are P(2, 5) and Q(2, 1).

Therefore, after dilation, the coordinates of the end points become

Thus, the coordinates of P' are (7, 17.5) and the co-ordinates of Q' are (7, 3.5).

7 0

2 years ago

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forsale [732]

It’s c. Where the two planes intersect

5 0

3 years ago

Please help. NO LINKS.

trasher [3.6K]

Answer:

the answer is A

y= 1.9x + 69

y=6x

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3 years ago

Simplify using order of operations 9 divided by 3 + 4 times 3 divided by 6

Alchen [17]

Answer:

$5$

Step-by-step explanation:

$1. \: 3 + 4 \times 3 \div 6 \\ 2. \: 3 + 12 \div 6 \\ 3. \: 3 + 2 \\ 4. \: 5$

7 0

3 years ago

A school P is 16km due west of a school Q. what is the bearing of Q from P

Irina-Kira [14]

Answer:

16Km due east of school P

Step-by-step explanation:

Given

A school P is 16km due west of a school Q

Thus, we can say that distance PQ = 16 km.

________________________________

now we have to find the bearing of Q from P

As distance is same

distance PQ = distance QP

Thus,

Distance will remain same of 16 km.

For direction,

If Q is west of P, then P will be east of Q $P------------------>Q$

as shown in figure P is west of Q,

now from point P , Q is west P.

Thus,

Bearing of School Q from P is 16Km due east of school P

7 0

4 years ago