Answer:b
Step-by-step explanation: you can correct your self and check your work by doing keep change flip
7/8
3/10 of 7/8 means 3/10 times 7/8=21/80
1hour=60mins
60 times 21/80=1260/80=15.75
answer is 15.75 mins
Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let = <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>
The z-score probability distribution for the sample mean is given by;
Z = ~ N(0,1)
where, = population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P( > 259 cm)
P( > 259 cm) = P( > ) = P(Z > -0.39) = P(Z < 0.39)
= <u>0.65173</u>
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
343 = 7*7*7, so the square root is 7*sqrt(7), because there is one 7 left in the square root after taking out the other 2.
Final answer:
7*sqrt(7), or about 18.52
Hope I helped :)