From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)
Hence, we can say that it's:
![\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5E%7Bc%7Dy%5E%7B5%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%283x%5E%7B2%7Dy%29%5E%7B3%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B6y%5E%7Bd%7D%7D)
![= \sqrt[3]{162x^{6}y^{3+d}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B162x%5E%7B6%7Dy%5E%7B3%2Bd%7D%7D)
Hence, c = 6 and d = 2
Equation: C=dπ
C=6·3.14
C=18.84
answer^^^
Answer:
3m times 2m = 1m
Step-by-step explanation:
because 4m- 1 =3m and m+2 =2m
Using the linear equation, T = 20x + 31, the total number of computers at the end of 2005 is: C. 191.
<h3>How to Use a Linear Equation?</h3>
A linear equation is expressed as y = mx + b, where x is a function of y, m is the rate of change and b is the y-intercept or starting value.
In the scenario stated, we are given the linear equation for total number of laptop computers at the school after 1997 as, T = 20x + 31.
Rate of change = 20
y-intercept/starting value = 31
x = 2005 - 1997 = 8
To find the total number of laptop computers at Grove High School at the end of 2005 (T), substitute x = 8 into the equation, T = 20x + 31.
T = 20(8) + 31
T = 160 + 31
T = 191 computers.
Thus, total number of computers at the end of 2005 is: C. 191.
Learn more about linear equation on:
brainly.com/question/15602982
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