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MaRussiya [10]
3 years ago
14

PLEASE HELP MATH EXPAND LOG

Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0

Answer:

½log3 + ½logx

Step-by-step explanation:

½(log(3x))

½(log3 + logx)

½logx + ½log3

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If its volume (Not so sure about surface area?) than its 432 inches^3
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At a red-tag sale, all items with red tags have been marked down by 49%. What should be the sale price of a DVD player having a
vampirchik [111]
Original price was $234.95
49% marked down = $234.95 *49 / 100 = $115.13

So now the sale price = original price - price of 49% marked down

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Answer: sale price of a DVD player having a red tag marked down by 49% should be $119.82
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The most important component of a physical structure is a solid foundation on which the rest of the structure sits. a strong fou
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The foundational concept of algebra is to use the alphabetical letters to find the unknown number.

Algebra is the concept that uses the alphabetical letters such as x, y, z, etc. to calculate the unknow numbers. here the letters are also called as variables. The values that are known in the expression as termed as constants.

The general operations performed on the algebra is

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  • Subtraction = x - y
  • Multiplication = x * y
  • Division = x / y

Here the alphabets x and y are called variables.

Order of operations:

The order of operation in algebra is given as follows

  • Perform all the operations inside the brackets
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To know mire about Algebra here

brainly.com/question/953809

#SPJ4

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2 years ago
The graphs shows the number of gallons of white paint that were mixed with gallons of blue paint
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3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 2 cos(t) + sin(2t),[0, π/2].
castortr0y [4]

Answer:

The absolute maximum is \frac{3\sqrt 3}2 and the absolute minimum value is 0.

Step-by-step explanation:

Differentiate of f both sides w.r.t.  t,

f(t)=2 \cos t+\sin 2t

\Rightarrow f'(t)=-2\sin t+2\cos 2t

Now take f'(t)=0

\Rightarrow -2\sin t+2\cos 2t=0

\Rightarrow 2\cos 2t=2\sin t

\Rightarrow \cos 2t=\sin t

\Rightarrow 1-2\sin ^2t =\sin t  \quad \quad  [\because \cos 2t = 1-2\sin ^2t]

\Rightarrow 2\sin ^2t+\sin t-1=0

\Rightarrow 2\sin ^2t+2\sin t-\sin t-1=0

\Rightarrow 2\sin t(\sin t+1)-1(\sin t+1)=0

\Rightarrow (\sin t+1)(2\sin t-1)=0

\Rightarrow \sin t+1=0  \;\text{and}\; 2\sin t-1=0

\Rightarrow \sin t =-1  \;\text{and}\;   \sin t =\frac 12

In the interval 0\leq t\leq \frac {\pi}2, the answer to this problem is \frac {\pi}6

Now find the second derivative of f(t) w.r.t.   t,

f''(t)=-2\cos t-4\sin 2t

\Rightarrow \left[f''(t)\right]_{t=\frac {\pi}6}=-2\times \frac {\sqrt 3}2-4\times \frac{\sqrt 3}2=-3\sqrt 3

Thus, f(t) is maximum at t=\frac {\pi}6 and minimum at t=0

\left[f(t)\right]_{t=\frac {\pi}6}=2\times \frac {\sqrt 3}2+\frac{\sqrt 3}2=\frac{3\sqrt 3}2\;\text{and}\;\left[f(t)\right]_{t=\frac{\pi}2}= 2\times 0+0=0

Hence, the absolute maximum is \frac{3\sqrt 3}2 and the absolute minimum value is 0.

7 0
3 years ago
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