If its volume (Not so sure about surface area?) than its 432 inches^3
Original price was $234.95
49% marked down = $234.95 *49 / 100 = $115.13
So now the sale price = original price - price of 49% marked down
sale price = $234.95 - $115.13 = $119.82
Answer: sale price of a DVD player having a red tag marked down by 49% should be $119.82
The foundational concept of algebra is to use the alphabetical letters to find the unknown number.
Algebra is the concept that uses the alphabetical letters such as x, y, z, etc. to calculate the unknow numbers. here the letters are also called as variables. The values that are known in the expression as termed as constants.
The general operations performed on the algebra is
- Addition = x + y
- Subtraction = x - y
- Multiplication = x * y
- Division = x / y
Here the alphabets x and y are called variables.
Order of operations:
The order of operation in algebra is given as follows
- Perform all the operations inside the brackets
- Perform the operations on roots and exponents
- Perform all the division and multiplication operations moving from left to right
- Perform all the addition and subtraction operations from left to right.
To know mire about Algebra here
brainly.com/question/953809
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Answer:
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Step-by-step explanation:
lknhojo
Answer:
The absolute maximum is
and the absolute minimum value is 
Step-by-step explanation:
Differentiate of
both sides w.r.t.
,


Now take 



![\Rightarrow 1-2\sin ^2t =\sin t \quad \quad [\because \cos 2t = 1-2\sin ^2t]](https://tex.z-dn.net/?f=%5CRightarrow%201-2%5Csin%20%5E2t%20%3D%5Csin%20t%20%20%5Cquad%20%5Cquad%20%20%5B%5Cbecause%20%5Ccos%202t%20%3D%201-2%5Csin%20%5E2t%5D)






In the interval
, the answer to this problem is 
Now find the second derivative of
w.r.t.
,

![\Rightarrow \left[f''(t)\right]_{t=\frac {\pi}6}=-2\times \frac {\sqrt 3}2-4\times \frac{\sqrt 3}2=-3\sqrt 3](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cleft%5Bf%27%27%28t%29%5Cright%5D_%7Bt%3D%5Cfrac%20%7B%5Cpi%7D6%7D%3D-2%5Ctimes%20%5Cfrac%20%7B%5Csqrt%203%7D2-4%5Ctimes%20%5Cfrac%7B%5Csqrt%203%7D2%3D-3%5Csqrt%203)
Thus,
is maximum at
and minimum at 
![\left[f(t)\right]_{t=\frac {\pi}6}=2\times \frac {\sqrt 3}2+\frac{\sqrt 3}2=\frac{3\sqrt 3}2\;\text{and}\;\left[f(t)\right]_{t=\frac{\pi}2}= 2\times 0+0=0](https://tex.z-dn.net/?f=%5Cleft%5Bf%28t%29%5Cright%5D_%7Bt%3D%5Cfrac%20%7B%5Cpi%7D6%7D%3D2%5Ctimes%20%5Cfrac%20%7B%5Csqrt%203%7D2%2B%5Cfrac%7B%5Csqrt%203%7D2%3D%5Cfrac%7B3%5Csqrt%203%7D2%5C%3B%5Ctext%7Band%7D%5C%3B%5Cleft%5Bf%28t%29%5Cright%5D_%7Bt%3D%5Cfrac%7B%5Cpi%7D2%7D%3D%202%5Ctimes%200%2B0%3D0)
Hence, the absolute maximum is
and the absolute minimum value is
.