Here's the graph with all of them colored in. I'm doing the areas on the other page.
7433700 I think but not sure
Answer:
Solve the equation so it is in the y=mx+b form.
Step 1. 6x+9y = 216
Step 2. 9y = -6x+216
Step 3. y = -6/9x+24
Step 4. Simplify/Reduce to get y = -2/3x+24
Since it is Parallel then the slope is the same so the slope is -2/3x.
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The maximum height of the shot is represented by the y-coordinate of the vertex, and the horizontal distance when the maximum height occurs is represented by the x-coordinate of the vertex.
Find x-coordinate of the vertex (horizontal distance)The function above is in standard form of ax² + bx + c = 0
In standard form of ax² + bx + c = 0, we could find the x-coordinate of the vertex by the formula of

Extract the information of a and b from the function f(x) = -0.06x² + 2.7x + 5.9
a = -0.06
b = 2.7
Input the value of a and b to the formula of x-coordinate of the vertex
x =

x =

x =

x =

x = 22.5
The x-coordinate represents the horizontal distance. So the maximum height occurs when the distance is 22.5 feet far from its point of release.
Find y-coordinate of the vertex (the maximum height)To find the maximum height, input the value of x-coordinate of the vertex to the function.
f(x) = -0.06x² + 2.7x + 5.9
f(22.5) = -0.06(22.5)² + 2.7(22.5) + 5.9
f(22.5) = -0.06(506.25) + 60.75 + 5.9
f(22.5) = -30.375 + 60.75 + 5.9
f(22.5) = 36.275
The maximum height is 36.275 feet