The equation of a circle centred at point (m,n) and radius r is given by
<span>(x-m)² + (y-n)² = r²
</span>-------------------------------------------------------------
Centre = (4,3)
radius = 5
Equation:
(x - 4)² + (y - 3)² = 5²
⇒ x² - 8x + 16 + y² - 6y + 9 = 25
⇒ x² + y² - 8x - 6y + 25 = 25
⇒ x² + y² - 8x - 6y = 0
The equation of the circle is x² + y² - 8x - 6y = 0
Hope it helps!
Volume = W*L*H
30 = 5*L*H old one
Volume = 2*5*L*H new one
Volume new one = 2*5*L*H =2*(5*L*H)=2*30=60
Answer is C
Answer:
option (D) 16.5
Step-by-step explanation:
Data provided:
Sleep time of , X = 15.9 is at the 10th percentile
Standard deviation, σ = 0.5 hour
also,
10th percentile of normal distribution is
Z = F⁻¹(0.10)
or
Z = - 1.28 (Using Standard Normal distribution)
Now,
or
X = μ + ( σ × Z )
or
μ = X - ( σ × Z )
on substituting the respective values, we get
μ = 15.9 - 0.5 × (-1.28)
or
μ = 16.5
Hence, the correct answer is option (D) 16.5
<span>14.3 years
Hope that helps! (:</span>
1 hamper box, curated by Jithu can be contained 5 cupcakes.
<h3>Calculation:</h3>
The total amount of cupcakes =665 nos.
Jithu wants to create a gift box, each of which contains 6 cupcakes.
We have to see first, whether 665 could be equally distributed or not.
Hence, 665/6= 110.84 unit
It is seen that the number is in a fraction.so, It can be said that 665 cakes cannot be equally distributed to each gift pack carrying 6 cakes.
Hence, 110*6=660 cupcakes.
∴665-660= 5 cupcakes in one box
So, it is concluded that Jithu could be prepared 110 gift boxes containing 6 cakes each & 1 box containing 5 cupcakes.
Learn more about cake-related problems:
brainly.com/question/25225029?referrer=searchResults
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