Option C:
The equation which matches the graph above is y = 4x - 4.
Solution:
Take any two points on the graph of the line.
Let the points are (0, -4) and (1, 0).
Here, 
Slope of the line:
m = 4
y-intercept of the line is the point where the line crosses at y-axis.
Here, the line crosses at y-axis is (0, -4).
y-intercept, (c) = -4
Equation of a line is
y = mx + c
y = 4x + (-4)
y = 4x - 4
The equation which matches the graph above is y = 4x - 4.
Option C is the correct answer.
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
42 square ft because 4 times 3 is 12 and 10 times 3 is 30. 30+12=42
Number 4 would be: C
And number 5 would be: C
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