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Serhud [2]
3 years ago
15

Solve the system of equations −4x+3y=−2 y=x−1 ​ x = y =

Mathematics
1 answer:
dolphi86 [110]3 years ago
4 0
Answer: x = -1 and y = -2

Step-by-step explanation:

So if you know y = x-1 you can plug that in where y is in the first equation

-4x + 3(x-1) = -2

Distribute the 3:

-4x +3x -3 = -2

Combine like terms:
-x -3 = -2

Add 3 to both sides:
-x = 1

Multiply by -1:
X = -1

Then you plug that into the other equation to get y=(-1)-1

Which is -2
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Which expression is a factor of 10 x 2 + 11 x + 3
Eduardwww [97]
Answer: the two factors are (5x + 3) and (2x + 1)

Explanation:

I will find the two factors of 10x² + 11x + 3.

You can use either the quadratic formula of factor.

I will use the quadratic formula:

1)    

x= \frac{b^2 +/- \sqrt{b^2-4ac}  }{2a}

x=  \frac{-11+/- \sqrt{11^2-4(10)(3)} }{(2)(10)}

x = -3/5 and x = -1/2

2) the factors are: x - (-3/5) = 0 and x - (-1/2) = 0

Simplify them.

3) x - (-3/5) = 0

5x + 3 = 0

4) x - (-1/2) = 0

2x + 1 = 0

5) Then the two factors are: (5x + 3) and (2x + 1).

6) verify:

(5x + 3)(2x + 1) = 10x² + 5x + 6x + 3 = 10x² + 11x + 3 which is the original expression.
7 0
3 years ago
After m minutes, an adult blinks a bout 10m+ 3 times. about how many times does an adult blink in 3 minutes. In two hours.
Yuki888 [10]
My answer is 16 cause if you add 10 and 3 and 3 the =16

8 0
4 years ago
A record store has 3,108 records evenly shared among 6 rows. How many records are in each row?
PilotLPTM [1.2K]

Answer:

518

i don't know if this needs much explaining.

3 0
3 years ago
Read 2 more answers
A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.​
Papessa [141]

<u>Answer:</u>

\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}

<u>Step-by-step explanation:</u>

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}

\bf \implies n_{cubes} = \dfrac{20cm \times  6cm \times 4cm .}{2cm  \times 2cm  \times 2cm } \\\\\bf\implies n_{cubes}  = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }

<h3><u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>

6 0
3 years ago
Convert to a mixed number: -16.04 over .2
Veseljchak [2.6K]

\dfrac{-16.04}{0.2}=-\dfrac{16.04\cdot100}{0.2\cdot100}=-\dfrac{1604}{20}=-80\dfrac{2:2}{20:2}=-80\dfrac{1}{10}

3 0
3 years ago
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