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Colt1911 [192]
3 years ago
11

The International Business Club starts the school year with $250.50 in their account. They spend $35 each month on activities. T

he Future Agricultural Leaders Club starts with $300 and spends $45.25 each month. Which equation can be used to find m, the number of months it will take for both accounts to have the same amount of money? 250.5 + 35m = 300 + 45.25m 250.5 – 35m = 300 – 45.25m 250.5m – 35 = 300m – 45.25 250.5m + 35 = 300m + 45.25
Mathematics
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

250.50 - 35m = 300 - 45.25m

Step-by-step explanation:

Whenever an equation asks for when it will take x (or m in this case) amount of things or time you should know that there will be 2 different equations that have to equal each other

The equation will be 250.50 - 35m = 300 - 45.25m

The 35m is being subtracted from 250.50 because they are losing money each time they spend. This also applies to 45.25m

Also 35m and 45.25m are variables because it says they spend that much money each month. They don't specify how many months, so we have to put a variable after it.

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The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is \left(\frac{-9}{2}, \frac{-3}{2}\right)

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

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Step-by-step explanation:

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