Answer:
-3/2,collinear.
Step-by-step explanation:
slope of PQ=(0-3)/(2-0)=-3/2
eq. of line PQ is
y-3=-3/2(x-0)
y-3=-3/2 x
or2y-6=-3x
or 3x+2y=6
if R(4,-3) lies on it,then
3(4)+2(-3)=6
12-6=6
or 6=6
which is true.
Hence points P,Q,R are collinear.
and line has aslope=-3/2
Ok here
$134,061.09
hope this helps
1/27
27^(b/3)/9^(a/2) = (27^(1/3))^b/(9^(1/2))^a = (3^b)/(3^a) = 3^(b-a)
= 3^(-(a-b)) = 3^-3 = 1/3^3 = 1/27
