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garri49 [273]
3 years ago
9

If a gardener fences in the total rectangular area shown in the illustration instead of just the square area, he will need twice

as much fencing to enclose the garden. How much fencing will he need?

Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

He needs 5x+56 ft

Step-by-step explanation:

To find how much of fencing he needs , we find the perimeter of the given figure

All sides are equal in a square

To find perimeter of the square we add all the sides

4 sides we have for the square

one side is x, so perimeter of square = x+x+x+x= 4x

Now we find perimeter of rectangle

Opposite sides of rectangle are equal

Here for rectangle we consider only three sides

because fourth side is common for rectangle and square

So perimeter of the rectangle (with 3 sides) = 28 +x+ 28 = 56+x

Total fencing = perimeter of square + perimeter of rectangle

4x + 56 + x= 5x+56


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<img src="https://tex.z-dn.net/?f=3x%2B9%2B2x%3Dx-2x-3" id="TexFormula1" title="3x+9+2x=x-2x-3" alt="3x+9+2x=x-2x-3" align="absm
V125BC [204]

Answer:

Step-by-step explanation:

Equation

3x + 9 + 2x = x - 2x - 3              

Solution

Combine all the like terms.

3x+2x+9 =  x - 2x - 3

5x + 9 = -x - 3                            Add x to both sides of the equation

5x+x +9 = -x+x -3                      Combine

6x + 9 = - 3                                Subtract 9 from both sides of the equation

6x+9-9 = - 3-9                           Combine

6x = -12                                      Divide both sides by 6

6x/6 = -12/6

x = - 2

Answer x = - 2

3 0
2 years ago
Read 2 more answers
A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo
katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the boxV=x^2z

Volume of the box=12 ft^3\\

Therefore, x^2z=12\\z=\frac{12}{x^2}

The material for the base costs \$0.17/ft^2, the material for the sides costs \$0.10/ft^2, and the material for the top costs \$0.13/ft^2.

Area of the base =x^2

Cost of the Base =\$0.17x^2

Area of the sides =4xz

Cost of the sides==\$0.10(4xz)

Area of the Top =x^2

Cost of the Base =\$0.13x^2

Total Cost, C(x,z) =0.17x^2+0.13x^2+0.10(4xz)

Substituting z=\frac{12}{x^2}

C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}

To minimize C(x), we solve for the derivative and obtain its critical point

C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2

Recall: z=\frac{12}{x^2}=\frac{12}{2^2}=3\\

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0
3 years ago
Below are two parallel lines with a third line intersecting them.
Allushta [10]
180-48= 132 ( I think)
8 0
3 years ago
Break apart 372*7 multiplication
Alona [7]
372 simplified is: 2*2*3*31. Thus, 372*7= 2*2*3*31*7. I believe that's what the question is asking for, Hope that helps. :)
7 0
3 years ago
Read 2 more answers
This a comprehension questins​
nikdorinn [45]

where is the question?????????

3 0
3 years ago
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