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3 years ago

What is 1 1/8 as a decmia

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

8 0

Do you mean as a decimal? 11.8

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If 8 men on a construction crew make up 40% percent of the entire crew, how many people are in the crew?

pochemuha

Answer:

Step-by-step explanation:

Since 40% of the crew are men, which means n. 40=8 n=8/. 40 n=20 total number of crew 20 - 8=12 are women

6 0

3 years ago

Read 2 more answers

Y is such that 4y _ 7<= 3y and 3y <= 5y +8. What range of values of y satisfies both inequalities

fgiga [73]

Answer:

Step-by-step explanation:

Given the inequality expressions

4y - 7 ≤ 3y and 3y≤5y+8

For 4y - 7 ≤ 3y

Collect like terms

4y - 3y ≤ 7

y ≤ 7

For 3y≤5y+8

Collect like terms

3y - 5y ≤ 8

-2y ≤ 8

y ≥ 8/-2

y ≥ -4

Combining both solutions

-4≤y≤7

<em>Hence the range of values of y that satisfies both inequalities is -4≤y≤7</em>

6 0

3 years ago

Help please:) and thx

Juli2301 [7.4K]

Answer:

yes

Step-by-step explanation:

4 0

3 years ago

I need help on How to do it

Sloan [31]

200g × 0.9 × 1/2 = 90 g

5 0

3 years ago

Simplify and answer the boxes.

s2008m [1.1K]

Answer:

$\huge\boxed{\dfrac{x^2+9^2}{x-3y}+\dfrac{6xy}{3y-x}=x-3y}$

Step-by-step explanation:

Domain:

$x-3y\neq0\Rightarrow x\neq3y$

$\dfrac{x^2+9y^2}{x-3y}+\dfrac{6xy}{3y-x}=\dfrac{x^2+9y^2}{x-3y}+\dfrac{6xy}{-(x-3y)}\\\\=\dfrac{x^2+9y^2}{x-3y}-\dfrac{6xy}{x-3y}=\dfrac{x^2+9y^2-6xy}{x-3y}\\\\=\dfrac{x^2-2(x)(3y)+(3y)^2}{3y-x}=\dfrac{(x-3y)^2}{3y-x}\\\\=\dfrac{\bigg[-1(3y-x)\bigg]^2}{3y-x}=\dfrac{(-1)^2(3y-x)^2}{3y-x}\\\\=\dfrac{1(x-3y)(x-3y)}{x-3y}=x-3y$

Used:

The distributive property: a(b + c) = ab + ac

(a - b)² = a² - 2ab + b²

6 0

3 years ago