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QveST [7]
4 years ago
7

How do you multiply 1.43 by -19 over -37

Mathematics
2 answers:
Serjik [45]4 years ago
5 0
 1.43 \cdot \frac{ -19 }{ -37 } = \frac{143}{100} \cdot \frac{19}{37}=\frac{2717}{3700}


grigory [225]4 years ago
4 0
Well, if your problem looks like this,

-19
1.43 x -----
-37

then you can simply put a 1 under the 1.43 and make it a fraction. It will look like this.

1.43 -19
----- x -----
1 -37

You can put a one on the bottom of any number because it won't change the number. A fraction is jut division, so if you divide 1.43 by 1 you'll still have 1.43 which is why the one doesn't change the number if you add it. Adding the one just makes it easier to multiply fractions.

Now you can multiply across with 1.43 x -19 to give you -27.17 in your numerator (the top number of the fraction). Then you multiply -37 by 1 and that stays as -37 which goes into the denominator (the bottom number of the fraction).

1.43 -19 -27.17
----- x ----- = --------
1 -37 -37

To simplify that completely, you can get rid of the two negative signs because that cancel each other out. Your final answer is

27.17
-------
37

Another way to solve this would've been to divide -19 by -37 and then multiply that decimal by 1.43, but I prefer answers in fraction form because there's no rounding or infinite decimals to deal with.
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8[x-y] use x=5 and y=2
Hoochie [10]

Answer:

24

Step-by-step explanation:

Plugin the value of x and y

8[x + y] = 8*[5 - 2]

            = 8 *3

            = 24

4 0
3 years ago
Read 2 more answers
Special Triangles
Ugo [173]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent trigonometric ratios and the exact values

cos30° = \frac{\sqrt{3} }{2} and tan30° = \frac{1}{\sqrt{3} } , then

cos30° = \frac{adjacent}{hypotenuse} = \frac{6}{m} = \frac{\sqrt{3} }{2} ( cross- multiply )

\sqrt{3} × m = 12 ( divide both sides by \sqrt{3} )

m = \frac{12}{\sqrt{3} } ← rationalise by multiplying numerator/ denominator by \sqrt{3} )

m = \frac{12}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = \frac{12\sqrt{3} }{3} = 4\sqrt{3}

-------------------------------------------------------------------------------

tan30° = \frac{opposite}{adjacent} = \frac{n}{6} = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} × n = 6 ( divide both sides by \sqrt{3} )

n = \frac{6}{\sqrt{3} } ← rationalise the denominator

n = \frac{6}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = \frac{6\sqrt{3} }{3} = 2\sqrt{3}

-----------------------------------------------------------------------------------

7 0
3 years ago
PLEASE HELP! WILL GIVE BRAINLIEST ONLY CORRECT ANSWER!! URGENT!
Katyanochek1 [597]

Answer:

A) x > -8

Step-by-step explanation:

-4x < 32

-x < 8

x > -8

7 0
3 years ago
Need help on 2,3,&amp; 4 please help will give brainliest
muminat
Im not so sure about Q2 but 3 and 4 are correct for sure.

8 0
3 years ago
If f(x) = 3x + 3, then f-1(x) =
tensa zangetsu [6.8K]
Mathematically, when you calculate the inverse function (f-1(x)), you’re switching the “inputs” (x) and the “outputs” (f(x)) and then re-solving the equation. So, you’d start with something like:

x = 3*f-1(x) + 3
x - 3 = 3*f-1(x)
(x - 3)/3 = f-1(x)

Your inverse formula would be (x - 3)/3. Hope this helps! (Hopefully Brainly doesn’t mess up the text format.)
7 0
4 years ago
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