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Evgesh-ka [11]
3 years ago
5

For what value of x will the line passing through the following pairs of points be vertical? K(−x, −7) and L(5, 0)

Mathematics
1 answer:
algol133 years ago
4 0

Answer:

It is actually -5

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The tens digit is twice the units digit. Reverse the digits, add 2 and the new number is 34 less than the original number. Find
inna [77]

Answer:

Step-by-step explanation: X and Y represent the digits.

The tens digit is twice the units digit.

The digit in the Tens place has 10× its base value, so we can set up equations to model the information given.

10x +y 10y +x are Original & Reversed numbers

X = 2y means the Tens digits is twice the units digit.

10y + x +2 = 10x +y - 34 models the statement: The reversed number plus two is 34 less than the original number.

Substitute 2y for x to solve for y

10y +2y +2= 10(2y) + y -34

Distribute and combine like terms

12y + 2 = 20y +y - 34

34 +2 = 21y -12y

36 = 9y Divide both sides to find the value of y.

4 = y

X = 2(4) Substitute 4 for y to find x

X = 8

Original number: 84 Reversed number: 48

Substitute into equation model

48 +2= 84 -34

50 = 50

True!

3 0
3 years ago
5 is equal to what fraction?
KiRa [710]

5 equals 5/1.  Simple as that.


8 0
2 years ago
HELP ASAP WILL GIVE 15 POINTS!!!
sladkih [1.3K]

Answer:

B

Step-by-step explanation:

Since its changing the y, we now it has to be outside the x. So its not A or D. Since it moves up, its a plus. This means its not c, so it has to be B.

5 0
3 years ago
PLEASE HELP I need the answer for this ASAP pleaseeeee
True [87]

Answer:

13

Step-by-step explanation:

f(x) = 5 \sqrt{x}  + 8 \\ f(1) = 5 \sqrt{1}  + 8 \\13

Hope this helps..

3 0
3 years ago
What is the constant of proportionality for the graph? The graph is attached
hichkok12 [17]
The answer is A. 0.5. 

When you go out 1 on the X-axis you go up 0.5 on the Y-axis, thus the ratio is 0.5.

This is not easy to see, but if you go out 10 on the X-axis, it is easy to see that the Y-axis is at 5. Again giving the ratio 5/10=0.5
5 0
3 years ago
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