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Ivanshal [37]
4 years ago
8

F ( x ) = x 3 − x 2 − 9 x + 9 is this a function ?

Mathematics
2 answers:
satela [25.4K]4 years ago
3 0

Answer:

36

Step-by-step explanation:

sineoko [7]4 years ago
3 0

Answer:

Yes.

Step-by-step explanation:

Yes this is a linear equation.

First we need to simplify the equation down. We can do this by working through all the indicated subtractions shown in this equation.

3x - 2x - 9x = -8x

f(x) = -8x + 9

This is a linear equation. Check your work on a graphing calculator.

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Which linear inequality is represented by the graph?
stich3 [128]

The linear equality y < 3x + 2 is represented by the graph attached.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An inequality is the non equal comparison of two or more numbers and variables.

The linear equality y < 3x + 2 is represented by the graph attached.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

6 0
2 years ago
LAY
marta [7]

Answer:

A

Step-by-step explanation:

how long is the ball in the air ?

that is the same as asking : after how many seconds will the ball hit the ground (= reach the height of 0) ?

so, that means we need to find the zero solution of h(t).

at what t is h(t) = 0 ?

when at least one of the factors is 0 :

2(-2 - 4t)(2t - 5)

we have 3 factors

2 : can never be 0.

(-2 -4t) : can only be 0 for negative t, which does not make sense in our scenario (we cannot go back in time, only forward).

(2t - 5) : is 0 when 2t = 5 or t = 2.5

so, A is the right answer.

FYI : the starting height (on the hill) is given by t = 0 :

2(-2 - 0)(0 - 5) = 2×-2×-5 = 20 ft

3 0
2 years ago
If you randomly pick a date in april, how mny equally likely outcomes are there.
ArbitrLikvidat [17]
There are 30 days in April, so if you randomly pick a date in April there are 30 equally likely outcomes
6 0
3 years ago
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
Lelu [443]
468.1 shoppers visited because of a coupon
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3 years ago
The equation of function h is h... PLEASE HELP MATH
Flura [38]

Answer:

Part A: the value of h(4) - m(16) is -4

Part B: The y-intercepts are 4 units apart

Part C: m(x) can not exceed h(x) for any value of x

Step-by-step explanation:

Let us use the table to find the function m(x)

There is a constant difference between each two consecutive values of x and also in y, then the table represents a linear function

The form of the linear function is m(x) = a x + b, where

  • a is the slope of the function
  • b is the y-intercept

The slope = Δm(x)/Δx

∵ At x = 8, m(x) = 2

∵ At x = 10, m(x) = 3

∴ The slope = \frac{3-2}{10-8}=\frac{1}{2}

∴ a = \frac{1}{2}

- Substitute it in the form of the function

∴ m(x) = \frac{1}{2} x + b

- To find b substitute x and m(x) in the function by (8 , 2)

∵ 2 = \frac{1}{2} (8) + b

∴ 2 = 4 + b

- Subtract 4 from both sides

∴ -2 = b

∴ m(x) = \frac{1}{2} x - 2

Now let us answer the questions

Part A:

∵ h(x) = \frac{1}{2} (x - 2)²

∴ h(4) = \frac{1}{2} (4 - 2)²

∴ h(4) = \frac{1}{2} (2)²

∴ h(4) =  \frac{1}{2}(4)

∴ h(4) = 2

∵ m(x) = \frac{1}{2} x - 2

∴ m(16) =  \frac{1}{2} (16) - 2

∴ m(16) = 8 - 2

∴ m(16) = 6

- Find now h(4) - m(16)

∵ h(4) - m(16) = 2 - 6

∴ h(4) - m(16) = -4

Part B:

The y-intercept is the value of h(x) at x = 0

∵ h(x) = \frac{1}{2} (x - 2)²

∵ x = 0

∴ h(0) = \frac{1}{2} (0 - 2)²

∴ h(0) =  \frac{1}{2} (-2)² =  

∴ h(0) = 2

∴ The y-intercept of h(x) is 2

∵ m(x) = \frac{1}{2} x - 2

∵ x = 0

∴ m(0) = \frac{1}{2} (0) - 2 = 0 - 2

∴ m(0) = -2

∴ The y-intercept of m(x) is -2

- Find the distance between y = 2 and y = -2

∴ The difference between the y-intercepts of the graphs = 2 - (-2)

∴ The difference between the y-intercepts of the graphs = 4

∴ The y-intercepts are 4 units apart

Part C:

The minimum/maximum point of a quadratic function f(x) = a(x - h) + k is point (h , k)

Compare this form with the form of h(x)

∵ h = 2 and k = 0

∴ The minimum point of the graph of h(x) is (2 , 0)

∵ k is the minimum value of f(x)

∴ 0 is the minimum value of h(x)

∴ The domain of h(x) is all real numbers

∴ The range of h(x) is h(x) ≥ 2

∵ m(8) = 2

∵ m(14) = 5

∵ h(8) = \frac{1}{2} (8 - 2)² = 18

∵ h(14) = \frac{1}{2} (14 - 2)² = 72

∴ h(x) is always > m(x)

∴ m(x) can not exceed h(x) for any value of x

<em>Look to the attached graph for more understand</em>

The blue graph represents h(x)

The green graph represents m(x)

The blue graph is above the green graph for all values of x, then there is no value of x make m(x) exceeds h(x)

7 0
3 years ago
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