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GREYUIT [131]
2 years ago
6

(-2, 11) & (5,6) What is the slope of the equation between these two points?

Mathematics
1 answer:
ololo11 [35]2 years ago
8 0

Answer:

m =\dfrac{-5}{7}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • Two points (-2,11) and (5,6) .

And we need to find out the slope of the equation between the two points. The slope of the line passing through two points , is given by ,

\implies Slope (m) =\dfrac{ y_2-y_1}{x_2-x_1}

  • Here the two points are (-2,11) and (5,6) .So put on the respective values ,

\implies Slope (m) =\dfrac{ 11 - 6}{-2-5}\\\\\implies Slope = \dfrac{5}{-7} \\\\\implies Slope = \dfrac{-5}{7}

<u>Hence</u><u> the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> line</u><u> is</u><u> </u><u>-</u><u>5</u><u>/</u><u>7</u><u> </u><u>.</u>

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Answer:

Option D) F

Step-by-step explanation:

we have

y < -2x+10 -----> inequality A

The solution of the inequality A is the shaded area below the dashed line y=-2x+10

The y-intercept of the dashed line is (0,10)

The x-intercept of the dashed line is (5,0)

y < \frac{1}{2}x-2 ----> inequality B  

The solution of the inequality B is the shaded area below the dashed line y=\frac{1}{2}x-2

The y-intercept of the dashed line is (0,-2)

The x-intercept of the dashed line is (4,0)

The solution of the system of inequalities is the shaded area between the two dashed lines

see that attached figure

Remember that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must lie on the shaded area of the solution

therefore

The solution are the points

E, F and G

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3 years ago
A grid shows the positions of a subway stop and your house. The subway stop is located at (-1, 0) and your house is located at (
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3 years ago
Doing some homework right now :) Need help on this problem
pychu [463]

Answer:

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Step-by-step explanation:

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A clock was reading the time accurately on Friday at noon. On Monday at 6pm the clock was running late by 468 seconds. On averag
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The clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

The clock was still accurate by Friday noon. The clock was late by 468 seconds by Monday, 6 pm.

To solve the problem, we must:

Know how many 30-minutes have passed during the time period.

1 day = 24 hours

1 hour = 60 minutes = 2 × (30 minutes)

1 day = 24 hours × 2 × (30 minutes)

1 day = 48 × (30 minutes)

Thus, there are 48, 30-minutes in a day. On Friday, however, we start counting at noon, which is half of the day. Moreover, on Monday, the mark is only up to 6 pm, which is three-fourths of the day.

Friday = 48 × \frac{1}{2} = 24

Saturday = 48

Sunday = 48

Monday = 48 × \frac{3}{4} = 36

TOTAL = 24 + 48 + 48 + 36 = 156

Therefore, the total number of 30-minutes that have passed is 156. There were 156, 30-minutes that passed during the time period.

Divide the number of total seconds late by the number of 30-minutes passed.

That is, the number of total seconds late= 468 seconds ÷ 156

= 3 seconds  

Therefore, the clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

To learn more about clock problems visit:

brainly.com/question/27122093.

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2 years ago
From a top of a building 20 m high if the angle of elevation top of a vertical pole is 30 degree.and the angle of depression of
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Answer:

The height of the pole is 26.64 metres.

Step-by-step explanation:

Please kindly see the attached for explanation

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