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ryzh [129]
3 years ago
7

You are a running a concession stand selling hot dogs and sodas each hot dog costs .75 cents and each soda costs $1.25. You sold

27 more sodas than hot dogs. if you made a total of $257.75. How many sodas and hot dogs did you sell?
Mathematics
2 answers:
tatiyna3 years ago
6 0
<span>Each hot dog costs $ 1.50 and each soda costs $ .50. You made a total of $ 78.50. You sold a total of 87 hot dogs and sodas combined. You must report the number of hot dogs and soda's sold. How many hot dogs and soda's were sold? 

Quantity Equation: h + s = 87
Value Equation:: 1.5h+0.5s=78.50

Multiply thru the Quantity Equation by 15
Multiply thru the Value Equation by 10.

15h + 15s = 15*87
15h + 5s = 785</span>Subtract and solve for "s":<span>10s = 520
</span>s = 52 (# of soda's sold)
<span>
Solve for h:
h + s = 87
h + 52 = 87
h = 35 (# of hot dog's sold)</span>
anastassius [24]3 years ago
5 0
<span>Each hot dog costs $ 1.50 and each soda costs $ .50. You made a total of $ 78.50. You sold a total of 87 hot dogs and sodas combined. You must report the number of hot dogs and soda's sold. How many hot dogs and soda's were sold? 

Quantity Equation: h + s = 87
Value Equation:: 1.5h+0.5s=78.50

Multiply thru the Quantity Equation by 15
Multiply thru the Value Equation by 10.

15h + 15s = 15*87
15h + 5s = 785</span>Subtract and solve for "s":<span>10s = 520
</span>s = 52 (# of soda's sold)
<span>
Solve for h:
h + s = 87
h + 52 = 87
h = 35 (# of hot dog's sold)

hope i helped^-^</span>
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GrogVix [38]

Answer:

  • See below

Step-by-step explanation:

This equation is solved if one of the following 2 conditions is met

1.

  • (x² + 1) / 10 is between 1 and 2

and

  • 10 / (x² + 1)  is between 0 and 1

<u>Solve this:</u>

  • 1 < (x² + 1) / 10 < 2
  • 10 < x² + 1 < 20
  • 9 < x² < 19
  • 3 < |x| < √19
  • x ∈ (- √19, - 3) ∪ (3, √19)
  • 0 < 10 / (x² + 1) < 1
  • x² + 1 > 10
  • x² > 9
  • |x| > 3

Solution for this case is x ∈ (- √19, - 3) ∪ (3, √19)

2.

  • (x² + 1) / 10 is between 0 and 1

and

  • 10 / (x² + 1)  is between 1 and 2

<u>Solve this:</u>

  • 0 < (x² + 1) / 10 < 1
  • 0 < x² + 1 < 10
  • - 1 < x² < 9
  • 0 ≤ |x| < 3
  • x ∈ ( - 3, 3)
  • 1 < 10 / (x² + 1) < 2
  • x² + 1 < 10 ⇒ x² < 9 ⇒ |x| < 3
  • x² + 1 > 5 ⇒ x² > 5 ⇒ |x| > √5

Solution for this case is x ∈ (- 3, - √5) ∪ (√5, 3)

8 0
3 years ago
Drop me a workout routine that i can do in my room . LOL
Slav-nsk [51]

Answer:

5 Pull Ups 10 push ups and 15 squats+ if you want 10 jumping jacks.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A bag of jellybeans has 20 watermelons jellybeans, 45 sour apple jellybeans, 30 orange jellybeans and 5 cotton candy jellybeans.
Ksju [112]
20/100 = 1/5



Add up the numbers (20, 45 , 30 ,5) then there are 20 watermelon flavoured ones so it will be 20/100=1/5
3 0
3 years ago
If both pairs of opposite angles of a quadrilateral are __________, then the quadrilateral is a parallelogram.
lara [203]

Answer:

Obtuse

Step-by-step explanation:

Angles of a parallelogram are supplementary to it's adjacent angles . One pair of opposite angles of a parallelogram is obtuse & other pair is acute . Here in the figure , ∠DAB & ∠BCD are obtuse angles and also opposite to each other whereas ∠ADC & ∠ABC are acute angles and are opposite to each other.

5 0
3 years ago
Really need helpppp?!
user100 [1]

Answer:

6.43

pls follow me and mark brainliest ...thank u

Step-by-step explanation:

length of side x will be

Tan tita = opp/adjacent

tan65 = x/3

tan 65 is 2.14

so...you are left with 2.14=x/3

by cross multiplying

x= 2.14 × 3

= 6.43

5 0
3 years ago
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