If the current in a circuit is 2 +j2 amps and the resistance is 3-j2 ohms, what is the voltage
1 answer:
Answer:
The voltage is 10 + 2j volts.
Step-by-step explanation:
Ohm's first law:
By Ohm's first law, the voltage is the multiplication of the current by the resistance, that is:

The voltage is measured in Volts, the current in amps and the resistance in ohms.
In this question:
Both the current and the resistance have complex parts. We have to know that:

We have that:

Then





The voltage is 10 + 2j volts.
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