Answer:
Explanation:
The following program is written in Java and creates the divBySum method using a enhanced for loop. In the picture attached below I have provided an example of the output given if called using the array provided in the question and a divisible parameter of 3.
public static int divBySum(int[] arr, int num) {
int sum = 0;
for (int x : arr) {
if ((x % num) == 0) {
sum += x;
}
}
return sum;
}
Answer:
Here is the C++ program:
#include <iostream> //to use input output functions
using namespace std; //to identify objects cin cout
int main(){ //start of main method
double risingLevel; //declares a double type variable to hold rising level
cin>>risingLevel; //reads the value of risingLevel from user
cout<<"Level: "<<risingLevel<<endl; //displays the rising level
cout << "Years: 5, Rise: " << risingLevel * 5<<endl; //displays the rise in ocean level over 5 years
cout << "Years: 10, Rise: " << risingLevel * 10<<endl; //displays the rise in ocean level over 10 years
cout << "Years: 50, Rise: " << risingLevel * 50<<endl; //displays the rise in ocean level over 50 years
}
Explanation:
The program works as follows:
Lets say the user enters rising level 2.1 then,
risingLevel = 2.1
Now the first print (cout) statement :
cout<<"Level: "<<risingLevel<<endl; prints the value of risingLevel on output screen. So this statement displays:
Level: 2.1
Next, the program control moves to the statement:
cout << "Years: 5, Rise: " << risingLevel * 5<<endl;
which computes the rise in ocean levels over 5 years by formula:
risingLevel * 5 = 2.1 * 5 = 10.5
It then displays the computed value on output screen. So this statement displays:
Years: 5, Rise: 10.5 Next, the program control moves to the statement:
cout << "Years: 10, Rise: " << risingLevel * 10<<endl;
which computes the rise in ocean levels over 10 years by formula:
risingLevel * 10 = 2.1 * 10 = 21
It then displays the computed value on output screen. So this statement displays:
Years: 10, Rise: 21
Next, the program control moves to the statement:
cout << "Years: 50, Rise: " << risingLevel * 50<<endl;
which computes the rise in ocean levels over 50 years by formula:
risingLevel * 50 = 2.1 * 50 = 105
It then displays the computed value on output screen. So this statement displays:
Years: 50, Rise: 105 Hence the output of the entire program is:
Level: 2.1 Years: 5, Rise: 10.5 Years: 10, Rise: 21 Years: 50, Rise: 105
The screenshot of the program and its output is attached.
