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DiKsa [7]
4 years ago
5

Can someone please help me Solve 5x + 1 > 6?

Mathematics
2 answers:
natka813 [3]4 years ago
5 0

Answer:x>1

Step-by-step explanation:

lapo4ka [179]4 years ago
3 0

Answer:

x=2

Step-by-step explanation:

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What is the the answer to 3{2b+4} + 12b +6= 54
jarptica [38.1K]

Answer:

b=2

Step-by-step explanation:

Get rid of the parenthesis using distributive property:

6b+12+12b+6=54

Simplify

18b+18=54

subtract 18 from both sides

18b=36

divide by 18 on both sides

b=2

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3 years ago
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Calculate the volume of a cylindrical paint can with a diameter of 3 in and a height of 8 in.
Hoochie [10]

Answer:

Volume = 18 * pi in^3   OR IF pi=3.14 THEN   Volume = 56.52 in^3

Step-by-step explanation:

Volume = Area(circle) * Height

Volume = pi*(diameter/2)^2 *Height

Volume = pi* 2.25 * 8

Volume = 18 * pi in^3

And if pi=3.14 then:

Volume = 56.52 in^3

6 0
3 years ago
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Which expression is equivalent to StartFraction RootIndex 7 StartRoot x squared EndRoot Over RootIndex 5 StartRoot y cubed EndRo
Softa [21]

Answer:

D (x^7/2)(y^-5/3)

Step-by-step explanation:

6 0
3 years ago
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3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

5 0
3 years ago
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