Ok so I feel like the answer is A
Answer:
(1, 2/3) (-1, -1) are the points. use the slope formula to find the slope y2-y1/x2-x1
(-1 - 2/3) / (-1 -1) (answer both sides of the division side)
-5/3 / -2 (divide)
slope = 5/6 (the slope)
plug in values you know into point-slope form (y -y1) = m(x-x1)
y - (-1) = 5/6 (x - (-1) (i chose the easier point to plug in. two neg. make a pos. )
y +1 = 5/6 (x +1) (use the distributive property)
y +1 = 5/6x+5/6 (subtract 1 from both sides)
y = 5/6x - 1/6 or B (this is the equation)
Step-by-step explanation:
I hope this helped :))
9514 1404 393
Answer:
- a) 7
- b) -27
- c) 18
- d) 8
- e) 2
- f) 1
Step-by-step explanation:
The limit of any polynomial function at a point is the value of the polynomial at that point. A polynomial is defined and continuous for all values of the independent variable.
The limit of a rational function at a "hole" is the value of the simplified function at that point.
1a) lim = 4+3+2-2 = 7
1b) lim = (3)(-3)(3) = -27
1c) lim = 3^2+9 = 18
1d) lim = (x+4) = 4+4 = 8
1e) lim = 3x+1 = 3(1/3) +1 = 2
1f) lim = x^2/x^2 = 1
_____
The expressions of (e) and (f) can be simplified by factoring the difference of squares: a^2 -b^2 = (a -b)(a +b). In each case, one of the factors cancels the one in the denominator, so the remaining function can be evaluated at the limit point.
As x approaches infinity, the only terms of a rational expression that matter are those of the highest degree in numerator and denominator. (There's a little more to it if the numerator has a higher degree than the denominator.)
<span>A=2pie r^2 + 2pie rh so get h alone.
first take out the common factor of 2pie 2, so A=2pie r (r+h)
then divide by 2pie r, A/2pie r= r+h
then subtract r, so (A/2pie r) - r= h</span>