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3 years ago

Translate the phrase into a math expression.

Mathematics

1 answer:

Nonamiya [84]3 years ago

8 0

Its d 20 / (1+4)...........................................................................

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Line segment CD begins at (−1,1) and ends at (4,1). The segment is translated 2 units down to form line segment C'D'. Line segme

dusya [7]

Answer:

D' = (4, -1)

Step-by-step explanation:

Translation down by 2 units subtracts 2 from the y-coordinate. The x-coordinate remains unchanged. You can see this in the descriptions of C and C':

C = (-1, 1)
C' = (-1, -1) . . . . . 2 is subtracted from y=1 to get y=-1

Likewise:

D = (4, 1)
D' = (4, -1)

The translated segment is still a horizontal segment, now at y=-1 instead of at its previous position of y=1.

6 0

4 years ago

The volume of a room is 640 cubic feet. If the length is 10 feet and the width is 4 feet, find the height

lorasvet [3.4K]

Answer:

Step-by-step explanation:

Divide 640 by 40.

7 0

2 years ago

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Please help me with this question. There are 7 boys in a class of 13 student

xxTIMURxx [149]

What is the question?

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3 years ago

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(6+√25)/(4-√3) can be written in the form of (2+s√3)/13 where r and s are both integers what are the values of r and s

cestrela7 [59]

Answer:

r = 33

s = 18

Step-by-step explanation:

Given expression is $\frac{6+\sqrt{27}}{4-\sqrt{3}}$ .

Multiply numerator and denominator with the conjugate of (4 - √3).

$\frac{(6+\sqrt{27})(4+\sqrt{3})}{(4-\sqrt{3})(4+\sqrt{3})}$

= $\frac{4(6+\sqrt{27})+\sqrt{3}(6+\sqrt{27})}{4^{2}-(\sqrt{3})^2}$

= $\frac{24+4\sqrt{27}+6\sqrt{3}+\sqrt{81})}{16-3}$

= $\frac{24+12\sqrt{3}+6\sqrt{3}+\sqrt{81})}{16-3}$

= $\frac{24+18\sqrt{3}+9}{13}$

= $\frac{33+18\sqrt{3}}{13}$

Now compare this expression with $\frac{r+s\sqrt{3} }{13}$

r = 33

s = 18

3 0

3 years ago

Can someone please help me! Big ideas 8.4 number 20

Harlamova29_29 [7]

<u>Answer:</u> The perimeter is about 20.26 units

<u>Step-by-step explanation:</u>

To calculate the distance between the points, we use the formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

where,

d = distance

$x_2\text{ and }x_1$ are the coordinates of the points on x-axis

$y_2\text{ and }y_1$ are the coordinates of the points on y-axis

For the given points:

B(0,3), C(4,-1), E(2,-3) and F(-2,1)

Calculating the distance BC:

$x_2=4\\x_1=0\\y_2=-1\\y_1=3$

Putting values in above equation, we get:

$BC=\sqrt{(4-(0))^2+(-1-3)^2}\\\\d=\sqrt{16+16}=5.66units$

Calculating the distance CE:

$x_2=2\\x_1=4\\y_2=-3\\y_1=-1$

Putting values in above equation, we get:

$CE=\sqrt{(2-(4))^2+(-3-(-1))^2}\\\\d=\sqrt{36+4}=4.47units$

To calculate the perimeter of a rectangle, we use the equation:

$Perimeter=2(l+b)$ ....(1)

where,

l = length of the rectangle = BC = 5.66 units

b = breadth of the rectangle = CE = 4.47 units

Putting values in equation 1, we get:

$Perimeter=2(5.66+4.47)\\\\Perimeter=20.26 units$

Hence, the perimeter is about 20.26 units

7 0

3 years ago