Answer:
Step-by-step explanation
You must find the common denominator for all of them.
A is correct. 13 x 2 is 26 and 14 x 2 is 28. Therefore, 13/14 is greater than 25/28.
B is not correct. 4 x 5 is 20 and 9 x 5 is 45. 4/9 is actually less than 21/45.
C is not correct. 5 x 2 is 10 and 6 x 2 is 12. 5/6 is actually less than 11/12.
D is not correct. 4 x 5 is 20 and 5 x 5 is 25. 4/5 is actually less than 8/25.
Let g and b represent the numbers of grandstand and bleacher tickets sold.
.. g + b = 5716 . . . . . . . . . total number of tickets sold
.. 65g +40b = 341690 . . value of tickets sold
Using the first equation
.. g = 5716 -b
Sustituting into the second equation
.. 65(5716 -b) +40b = 341690
.. -25b + 371540 = 341690 . . . . . collect terms
.. -25b = -29850 . . . . . . . . . . . . . . subtract 371540
.. b = 1194 . . . . . . . . . . . . . . . . . . . . divide by -25
1194 bleacher tickets were sold.
1-(-4)^2
1-(-4 times -4)
1-(16)
1-16
-15
Answer:
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
Step-by-step explanation:
The sample proportion is p2= 7/27= 0.259
and q2= 0.74
The sample size = n= 27
The population proportion = p1= 0.4
q1= 0.6
We formulate the null and alternate hypotheses that the new program is effective
H0: p2> p1 vs Ha: p2 ≤ p1
The test statistic is
z= p2- p1/√ p1q1/n
z= 0.259-0.4/ √0.4*0.6/27
z= -0.141/0.09428
z= -1.496
The significance level ∝ is 0.05
The critical region for one tailed test is z ≤ ± 1.645
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
I think it's the second equation. I could be wrong but I think that's what it is
