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kifflom [539]
3 years ago
14

There is a 60% chance that your flight will leave on time

Mathematics
2 answers:
OLEGan [10]3 years ago
6 0
A 40% chance





Unless!
*wispers*
It’s a trick question?
olya-2409 [2.1K]3 years ago
3 0

Answer:

The correct answer would be 40

Step-by-step explanation:

40+60=100

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What is the measure of DEF?
abruzzese [7]

Answer:

66°

Subtract 78 - 12 = 66

5 0
3 years ago
Determine which, if any, of the three statements are equivalent.
patriot [66]

Answer:

Statement (b) is equivalent to statement (c), but neither is equivalent to statement (a).

Step-by-step explanation:

Let F denote that "Fido is our fish's name" and let R denote that "Rex is our dog's name". The statements listed in this question would then become:

  • (a) F \implies R;
    F implies R.
  • (b) \lnot ((\lnot F) \land (\lnot R));
    not ((not F) or (not R)).
  • (c) F \lor R;
    F or R.

Apply de Morgan's Law \lnot (P \land Q) \iff (\lnot P) \lor (\lnot Q) to rewrite statement (b). Let P = (\lnot F) and Q = (\lnot R). By de Morgan's Law:

\begin{aligned} & \lnot ((\lnot F) \land (\lnot R)) \\ \iff \; & \lnot (P \land Q)\\ \iff \; & (\lnot P) \lor (\lnot Q) && (\text{by de Morgan's Law}) \\ \iff \; & (\lnot (\lnot F)) \lor (\lnot (\lnot R)) \\ \iff \; & F \lor R\end{aligned}.

In other words, statement (b) \lnot ((\lnot F) \land (\lnot R)) is equivalent to statement (c) F \lor R.

Statement (a) F \implies R isn't equivalent to F \lor R.

For example, when F = \texttt{True} and R = \texttt{False}, F \implies R would be false since \texttt{True} does not imply \texttt{False}. However, for the same F and R, F \lor R would be true since F = \texttt{True}\!.

5 0
2 years ago
If u lost 17 points out of 35 on a test what grade would u get
Alla [95]
18/35 = ~51% 
You would get an F.
4 0
3 years ago
Read 2 more answers
Find the exact length of side a
pantera1 [17]

The figure is a scalene triangle, and the exact length of side a is √13

<h3>How to determine the exact length of side a?</h3>

To calculate the length of a, we make use of the following law of cosine

a² = b²  + c² - 2bc * cos(A)

Using the values in the figure, we have:

a² = 3√2²  + 5² - 2 * 3√2 * 5 * cos(45)

Evaluate the expression

a² = 18  + 25 - 30

Evaluate the sum and the difference

a² = 13

Take the square root of both sides

a = √13

Hence, the exact length of side a is √13

Read more about law of cosines at:

brainly.com/question/4372174

#SPJ1

5 0
2 years ago
Most soybeans grown in the United States are genetically modified to, for example, resist pests and so reduce use of pesticides.
garri49 [273]

Answer:

Interval [0.67;0.95]

Step-by-step explanation:

Hello!

You need to estimate the population proportion of grain-handling facilities that detect GM beans in shipments with a confidence interval.

The formula you have to use is:

^ρ±Z_{1-\alpha/2} * √(^ρ*(1-^ρ)/n)

where ^ρ represents the sample proportion

^ρ= x/n = 17/21 = 0.809 ≅ 0.81

Confidence level 90%

Z_{1-0.0.05} = Z_{0.95} = 1.64

Interval

0.81±1.64 * √((0.81*0.19)/21)

0.81±0.140

[0.67;0.95]

With a confidence level of 90% you'd expect that the interval [0.67;0.95] contains the population proportion of grain-handling facilities that detect GM beans in shipments.

Remember:

The confidence level of an interval is the probability under which it is built. This probability indicates that if they build 100 confidence intervals, we expect 90 to contain the value of the population mean we are trying to estimate.

The bigger the confidence level, the bigger is the chance that it contains the estimated parameter, but then again, if you were to study the whole population there is no chance you'll miss the parameter.

The smaller the confidence level, there are fewer chances that it will contain the estimated parameter, but if it does, the estimation would be more accurate than with a bigger level.

You can think it like this, a shooter that hits the target at a distance of 5 meters (low confidence level) is way better than a shooter that hits the target at a distance from 20 cm (high confidence level)

90% Confidence level is acceptable enough to have an accurate estimation of the population parameter.

I hope it helps!

8 0
3 years ago
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