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Solnce55 [7]
3 years ago
14

What’s 2 3/4 divided by 2??

Mathematics
2 answers:
pychu [463]3 years ago
6 0
First u do 2• 4 and u will get 8, add the by 3 and u will get 11. Re-write ur expression as 11/4, u divid this and get 2.75, divide 2.75 by 2 and u will get 1.375
Alex17521 [72]3 years ago
5 0

Answer: 1.375


Step-by-step explanation:

Im not good at it, but this may be right?

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makkiz [27]
Solve for p by simplifying both sides of the equation, then isolation the variable
p = 1 + m/2

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What is the value of y in the equation 5x + 2y = 20, when x = 0.3?
garik1379 [7]
Y=9.25 because 5x0.3=1.5 you move constents to the right hand side and it becomes -1.5 then you do the rest and the answers is 9.25
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A piggy bank contains 80 nickels and dimes the value of the coins is 5.15
dimaraw [331]
Answer: the amount of dimes is $1.15 this is also equivalent to 11 dimes and an extra nickel.

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5 0
2 years ago
The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10
Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

N\sim Pois(0.2)

P(N=r)=\frac{e^{-np}(np)^r}{r!}

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}

P(N=0)=\frac{e^{-0.2}}{1}

P(N=0)=e^{-0.2}

P(N=0)=0.8187

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute r\geq 2 in formula,

P(N\geq 2)=1-P(N

P(N\geq 2)=1-[P(N=0)+P(N=1)]

P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]

P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]

P(N\geq 2)=1-[0.8187+0.1637]

P(N\geq 2)=1-0.9825

P(N\geq 2)=0.0175

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0
3 years ago
What is the slope of this line?
Rasek [7]

-1 will be the answer.

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2 years ago
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