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3 years ago

Math help pls, thank u

Mathematics

2 answers:

Tatiana [17]3 years ago

7 0

Answer:

11x+1

Step-by-step explanation:

First, lets ignore all the functions it is giving us. Ignore everything not important at this second; sometimes it can cloud some people's ability to process problems.

We need to look. It asks us for area. Area is length times width. We have the area, we have the width, but we need the length. So we need to divide!

$\frac{66x^{2} + 17x + 1}{6x+1}$ Is going to be our equation! Now, we just need to simplify!

First, lets factor the top function!

66 times 1 is 66, so we need two numbers that add to 17 and multiply to 66.

Off the top of my head, 6 and 11 seem like a perfect match! They add to 17, and multiply to 66!

So now lets sub these in for 17x!

$66x^{2} + 11x + 6x + 1$

Now lets factor!

$(66x^{2} + 11x) ==> 11x(6x + 1)\\(6x + 1) ==> 1(6x+1)\\(11x + 1)(6x+1)$

Now lets get back to the original equation!

$\frac{(11x+1)(6x+1)}{6x+1}$

We can simply cross out the (6x+1), since there is one on each side, leaving us with 11x+1!

So the length of the top surface, h(x) = 11x+1!

Hope this helps!

Lubov Fominskaja [6]3 years ago

6 0

Answer:

11x + 1

Step-by-step explanation:

f(x) = 66x² + 17x + 1

Factoring:

f(x) = (6x + 1) (11x + 1)

Area of a rectangle is width times length. So if g(x) = 6x + 1, then h(x) = 11x + 1.

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Describe the type of angles formed when you divide a circle into 4 equal parts

Taya2010 [7]

We know that

when a circle is divided into four equal parts, we will get 4 right angles
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360°/4=90° each part

see the attached figure to better understand the problem

8 0

3 years ago

The weight of a radioactive isotope was 96 grams at the start of an experiment. After one hour, the weight of the isotope was ha

zimovet [89]

The starting weight of the radioactive isotope = 96 grams

Weight after one hour is half of the starting weight. So the weight of the radioactive isotope after 1 hour = 48 grams

After 2 hours the weight is half as compared to the weight after previous hour. So weight after 2 hours = 24 grams.

This means, after every hour the weight is being halved. The half life of radioactive isotope is one hour.

Since after every hour, the weight is being halved, the weight of the isotope can be modeled by an exponential equation.

So,

Initial Weight = W₁ = 96
Change factor = 1/2 = 0.5

The general equation of the sequence will be:

$\\ \\ W_{t}=96(0.5)^{t}$

Here t represents the number of hours. Using various values of t we can find the weight of the radioactive isotope at that time.

We can plot the sequence using the above equation. The graph is attached below.

3 0

3 years ago

Read 2 more answers

PLEASE HELP I GIVE BRAINLIEST

melamori03 [73]

Here is my answer. I hope this is helpful.

4 0

3 years ago

HELP PLEASEEEE ITS DUE SOON! SHOW YOUR WORK & ILL GIVE BRAINLIEST I PROMISE

laiz [17]

Answer:

(2,10) or x=2 y=10

Step-by-step explanation:

1. Pick one of your equations and solve for a variable. I chose the first equation and solved for x.

5x-2y=-10 (Move the -2y to the other side, you need to do the opposite so you add +2y to -10)

5x=2y-10 (Divide the 5 from the x)

x=2/5y-2

2. Now take what you got for x and plug it into the x variable on the other equation.

3(2/5y-2)+6y=66 (Multiply 3 by 2/5y and -2)

6/5y-6=6y=66 (Move the -6 to the other side and add 6/5y to 6y)

36/5y=72 (Since the number on the y is a fraction, you must do the opposite to the other side)

y=72/1 x 5/36 (Flip your fraction and multiply it by the 72)

y=10

3. Now that you have one of the variables solved for, in order to get the other we must plug in what we have to the first equation.

5x-2(10)=-10 (Multiple 2 by 10)

5x-20=-10 (Move -20 to the other side, since you do the opposite add +20 to the -10)

5x=10 ( Divide 10 by 5)

x= 2

4. If needed, plug in the values of x and y to check your solution.

Hope this could help! :)

3 0

2 years ago

1 quarter 2 dimes 3 pennies how munch I have

vfiekz [6]

In total, you have 48 cents.
25+10+10+3= 48

Give 5 stars and brainliest answer if this helped please!

8 0

3 years ago