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boyakko [2]
3 years ago
14

id="TexFormula1" title=" - \sqrt{3.24 - \sqrt{1.44 + \sqrt{12.25} } } " alt=" - \sqrt{3.24 - \sqrt{1.44 + \sqrt{12.25} } } " align="absmiddle" class="latex-formula">
Can you help me solve this plz.
Mathematics
2 answers:
Ivenika [448]3 years ago
7 0

-sqa(3.24-sqa(1.44+sqa(12.25)))

= -sqa(3.24-sqa(4.94)) (since sqa(1.44+sqa(12.25))=sqa(4.94))

=-sqa(3.24-2.22261)

= - sqa(1.01739)

= - 1.00866

Harrizon [31]3 years ago
5 0

-sqa(3.24-sqa(1.44+sqa(12.25)))

= -sqa(3.24-sqa(4.94)) (since sqa(1.44+sqa(12.25))=sqa(4.94))

=-sqa(3.24-2.22261)

= - sqa(1.01739)

= - 1.00866

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PLS HELP pq has endpoints at p(-5,4) and q(7,-5).what is the midpoint of pq? what are the cordinates of the point 2/3 of the way
lara31 [8.8K]

Answer:

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b. (-0.2, 0.4)

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(x,y) = {(x1 + x2)/2 , (y1 + y2)/2}

From the question; (x1,y1) = (-5,4) and (x2,y2) = (7,-5)

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Length = √{(x2-x1)^2 + (y2-y1)^2}

Length = √{(7-(-5))^2 + (-5-4)^2}

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b. What we will use here is the internal division formula of the section formula;

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(x,y) = (mx2 + nx1)/m+ n , (my2 + ny1)/m + n

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(x1,y1) = (-5,4)

(x2,y2) = (7,-5)

So substituting these values, we have;

(x,y) = (2(7)+ 3(-5))/(2+3) , 2(-5) + 3(4)/(2+3)

(x,y) = (14 -15)/5 , (-10 + 12)/5

= (-1/5, 2/5) = (-0.2, 0.4)

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