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3 years ago

Find the slope of the line that contains (3, –2) and (4, 3). Can someone help fast please?

Mathematics

2 answers:

suter [353]3 years ago

7 0

Answer:

Step-by-step explanation:

M equals slope

M=3- -2/4-3

M=5/1

Therefore your slope would be 5

Elena L [17]3 years ago

6 0

Answer:

$\boxed {\boxed {\sf m=5}}$

Step-by-step explanation:

The slope of a line tells us the steepness and direction of a line. It is the change in y over the change in x (rise over run). It is calculated using the following formula:

$m= \frac{y_2-y_1}{x_2-x_1}$

In this formula, (x₁, y₁) and (x₂,y₂) are the coordinates the line passes through. The line contains (3, -2) and (4,3), therefore:

x₁ = 3
y₁ = -2
x₂ =4
y₂ = 3

Substitute the values into the formula.

$m= \frac{3 --2}{4-3}$

Solve the numerator.

3 --2 = 3+2 = 5

$m= \frac{5}{4-3}$

Solve the denominator.

$m= \frac{5}{1}=5$

The slope of the line is 5.

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Answer:

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Step-by-step explanation:

→ Find fg(x)

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

21 less than a number, multiplied by 4, results in 108.Find the value of the unknown number.

Anni [7]

21 - 4x = 108

Subtract 21 from both sides

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3 years ago

USA Today reports that about 25% of all prison parolees become repeat offenders. Alice is a social worker whose job is to counse

pychu [463]

Answer:

a) $P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039$

$P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469$

$P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211$

$P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422$

$P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316$

b) $E(X) = np = 4*0.75=3$

c) $Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866$

d) $P(X \geq 3) \geq 0.98$

And the dsitribution that satisfy this is $X\sim Binom(n=9,p=0.75$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=4, p=1-0.25=0.75)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039$

$P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469$

$P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211$

$P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422$

$P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316$

Part b

The expected value is givn by:

$E(X) = np = 4*0.75=3$

Part c

For the standard deviation we have this:

$Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866$

Part d

For this case the sample size needs to be higher or equal to 9. Since we need a value such that:

$P(X \geq 3) \geq 0.98$

And the dsitribution that satisfy this is $X\sim Binom(n=9,p=0.75$

We can verify this using the following code:

"=1-BINOM.DIST(3,9,0.75,TRUE)" and we got 0.99 and the condition is satisfied.

4 0

3 years ago