$\text{The vertex form:}\ y=a(x-h)^2+k\\\\f(x)=ax^2+bx+c\to h=\dfrac{-b}{2a},\ k=f(h)\\\\\text{We have}\ y=-x^2+6x+7\to f(x)=-x^2+6x+7\\\\a=-1,\ b=6,\ c=7\\\\h=\dfrac{-6}{2(-1)}=\dfrac{-6}{-2}=3\\\\k=f(3)=-3^2+6(3)+7=-9+18+7=16\\\\Answer:\ \boxed{y=-(x-3)^2+16}$

8 0

3 years ago

What is the solution of the inequality |2x+3|≤7?

Allushta [10]

Assuming you want to solve for x the result can vary. The result can be shown in multiple forms. Hope this helps!

Inequality Form:
−5≤x≤2
Interval Notation:
[−5,2]

6 0

2 years ago

The school that Stephen goes to is selling tickets to a choral performance on the first day of tickets sells the school so three

babymother [125]

Ybyhujim8ju gbyvtfrfr ybyhuj babyhood.hhybuj

4 0

2 years ago