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True [87]
2 years ago
14

Please say the answer step by step 2(10-4)2square+8

Mathematics
1 answer:
solong [7]2 years ago
5 0

Answer: -4

Step-by-step explanation: we will make the 4 to the power of 2 which is 4 multiply 4 equals 16 . Here are The steps .

2(10-16)+8

2(-6)+8

-12+8

-4

Hope it helps friend

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F(x)=-3x-4 what's the Inverness function ?
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First make x the subject:-

3x = F(x) + 4

x  = (F(x) + 4) / 3

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3 years ago
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8 0
3 years ago
How to solve this?? (-4)-(-8)+(-4)
kirill115 [55]
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6 0
2 years ago
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The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=
Leno4ka [110]
1 step: S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}, S_{3}=T_{1}+T_{2}+T_{3}, then
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2 step: T_{n}=T_{1}*q^{n-1}, then 
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T_{5}=T_{1}*q^{4}
T_{4}=T_{1}*q^{3}
T_{3}=T_{1}*q^{2}
and \left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right. will have form \left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right..

3 step: Solve this system  \left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right. and dividing first equation on second we obtain \frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}. So, \frac{(q-1)(q+1)}{q+1} = \frac{1}{2} and q-1= \frac{1}{2}, q= \frac{3}{2} - the common ratio.

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5 0
3 years ago
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