Question

If x=0 and x=3 then 3 divided by 2x to the second power minus 2 divided by x to the second power minus 3x

Answer 1

Answer: undefined in both cases.


Explanation:

1) Expression to evaluate:

$\frac{3}{2x^2} - \frac{2}{x^2-3x}$

2) You are asked to evaluate that expression for two different cases, x = 0 and x = 3.

3) First case: x = 0

The expression cannot be evaluated at x = 0, because the denominators (both  denominators) equal 0, and the division by 0 is not defined.

So, the answer is undefined.

4) Second case, x = 3

When you replace x = 3 you get:

$\frac{3}{2x^2} - \frac{2}{x^2-3x} = \frac{3}{2(3^2)} - \frac{2}{3^2-3(3)} = \frac{3}{18} - \frac{2}{9-9}$

Again, this result in a division by 0, so you conclude that it is undefined too.