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gayaneshka [121]
2 years ago
6

If x=0 and x=3 then 3 divided by 2x to the second power minus 2 divided by x to the second power minus 3x

Mathematics
1 answer:
Afina-wow [57]2 years ago
8 0
Answer: undefined in both cases.


Explanation:

1) Expression to evaluate:

\frac{3}{2x^2} - \frac{2}{x^2-3x}

2) You are asked to evaluate that expression for two different cases, x = 0 and x = 3.

3) First case: x = 0

The expression cannot be evaluated at x = 0, because the denominators (both  denominators) equal 0, and the division by 0 is not defined.

So, the answer is undefined.

4) Second case, x = 3

When you replace x = 3 you get:

\frac{3}{2x^2} - \frac{2}{x^2-3x} = \frac{3}{2(3^2)} - \frac{2}{3^2-3(3)} = \frac{3}{18} - \frac{2}{9-9}

Again, this result in a division by 0, so you conclude that it is undefined too.

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Answer:

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Step-by-step explanation:

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3 years ago
2( 10 - a^2 ) + 7a If ( a = 4 )Evaluate each expression
Lostsunrise [7]

Solution:

Given:

2(10-a^2)+7a

when a = 4, substitute for a in the expression;

\begin{gathered} 2(10-a^2)+7a=2(10-4^2)+7(4) \\ =2(10-16)+28 \\ =2(-6)+28 \\ =-12+28 \\ =16 \end{gathered}

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6 0
9 months ago
Determine f^-1(2) given the following: f(1 = -3f(2) = -2f(-1) = 2f(3) = -1
lana [24]

We assume that the function is as follows:

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Then, we have that:

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Therefore, the value for the function is f^-1(2) = -1/2 or

f^{-1}(2)=-\frac{1}{2}

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Answer:

Yes

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