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3 years ago

What is the lower quartile

Mathematics

2 answers:

saw5 [17]3 years ago

8 0

Answer:

The lower quartile value is the median of the lower half of the data. The upper quartile value is the median of the upper half of the data.

vekshin13 years ago

4 0

Answer:

ok, so have 3 quartiles you have q-1 (lower quartile) and q-2 (median of middle number) and q-3. But q-1 is the median of the lower half of the data.

Step-by-step explanation:

To find the lower quartile you have to first find the the median and to do so you line up all the numbers in order. Then one by one start from the left and go then to the right scratching each number off as you go. Then circle the middle number. Once you've done that and you have your median start from the beginning and repeat by scratching off each number from right to left or left to right then once you get to the medial you have your q-1 or your lower quartile

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A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra

VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that $N = 6$

4 blue, which means that $k = 4$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4$

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that $N = 6$

2 yellow, which means that $k = 2$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667$

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that $P(A) = 0.4 + 0.0667 = 0.4667$

Probability of both being the same color and blue:

40% probability that both are blue, which means that $P(A \cap B) = 0.4$

Desired probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571$

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0

2 years ago

Find the area of the figure. Round to the nearest tenth if necessary.

r-ruslan [8.4K]

Area = area of rectangle - area of 2 hemispheres
= 24 * 32 - pi * 12^2
= 315.6 sq units

5 0

2 years ago

Write your own explicit formula. List the first 4 terms and solve for the 10th term using the formula. (show your work)

Shalnov [3]

Answer:

See below.

Step-by-step explanation:

Formula:

$a_n = 3(n + 4)$

First term: n = 1

$a_1 = 3(1 + 4) = 15$

Second term: n = 2

$a_2 = 3(2 + 4) = 18$

Third term: n = 3

$a_3 = 3(3 + 4) = 21$

Fourth term: n = 4

$a_4 = 3(4 + 4) = 24$

Tenth term: n = 10

$a_{10} = 3(10 + 4) = 42$

4 0

2 years ago

(MIDDLE SCHOOL MATH) what is the answer for b)?

lesya692 [45]

Answer:

because it easily displays all of the info

7 0

3 years ago

Read 2 more answers

Round 3424 to the thousands place

Masja [62]

To solve this...

Look at the number and determine how far it is from 3,000 and 4,000

Since 424 is closer to 0

And not 500... (which rounds up)

Your answer is going to be 3,000

Hope this was helpful.

Please Rate, Thank, and mark brainliest ;)

8 0

3 years ago

Read 2 more answers