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BARSIC [14]
2 years ago
5

Calista runs one mile in 12 minutes, while Bethany runs one

Mathematics
1 answer:
romanna [79]2 years ago
6 0

Answer:

So, although Calista starts behind Bethany, she hopes to pass her sister

Step-by-step explanation:

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Which fraction is greater than 4/8?
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3/4
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Find the GCF of 56 and 40. <br>A.2<br>B.4<br>C.8<br>D.280
statuscvo [17]
<span><span>56:   222 7</span><span>40:   2225 </span><span>GCF:   222  </span></span>

The Greates Common Factor (GCF) is:   2 x 2 x 2 = 8

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3 years ago
Patti has two glue sticks that are partially used. One has 1/5 left, and one has 3/10 left. Which glue stick has more glue?
marishachu [46]

Answer:

the one with 3/10 left has more

Step-by-step explanation:

because 1/5 is equal to 2/10 and 3/10>2/10

8 0
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Please hurry! Timed! What is the scale factor in the dilation?
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C. 2

Hope this helps!
7 0
3 years ago
A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
3 years ago
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