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Nesterboy [21]
4 years ago
12

A) 48 m B) 36 m C) 18 m D) 7 m

Mathematics
1 answer:
liraira [26]4 years ago
7 0
Marcia: 1.5 meters tall / 2 meters long shadow
Building: unknown height / 24 meters long shadow

So 1.5/2 = x/24

You can cross multiply: 2x = 36
Divide: x = 18

So your answer is C).
You might be interested in
In the 1980s an average mortgage rate was around 18.5 how much less per month would a 150000 30 year mortgage by today if the cu
lianna [129]

Answer:

  $1516.69 per month less

Step-by-step explanation:

The formula for the monthly payment A on a loan of principal P, annual rate r, for t years is ...

  A = P(r/12)/(1 -(1 +r/12)^(-12t))

For the 18.5% loan, the monthly payment is ...

  A = 150000(.185/12)/(1 -(1 +.185/12)^(-12·30)) ≈ 2321.92

For the 5% loan, the monthly payment is ...

  A = 150000(.05/12)/(1 -(1 +.05/12)^-360) ≈ 805.23

The mortgage at 5% would be $1516.69 less per month.

7 0
4 years ago
Find the slope given the table of values
serg [7]

Answer:

slope=4

Step-by-step explanation:

m=\frac{change(y)}{change(x)}

m=\frac{-8-(-4)}{-5-(-4)}

m=\frac{-4}{-1}

m=4

3 0
3 years ago
Represent each of these relations on {1, 2, 3} with a matrix (with the elements of this set listed in increasing order).
Maru [420]

Answer:

(1 1), (1 2), (1 3), (2 2), (2 3) (3 3)

Step-by-step explanation:

discrete mathematics

4 0
3 years ago
The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. What is the distance between the point of inte
malfutka [58]

1. The area of the rhombus can be found by the formula

A=\dfrac{d_1\cdot d_2}{2}, where d_1,\ d_2 are rhombus's diagonals.

Note that d_1=4.5\ dm=45\ cm, then

540=\dfrac{45\cdot d_2}{2},\\ \\540\cdot 2=45d_2,\\ \\d_2=24\ cm.

2. The diagonals of rhombus are perpendicular and are bisectors of each other. Then the triangle formed with halfs of diagonals is right triangles with legs

\dfrac{d_1}{2}=22.5\ cm,\ \dfrac{d_2}{2}=12\ cm.

The hypotenuse of this triangle is the rhombus's side. By the Pythagorean theorem

\text{rhombus's side}^2=(22.5)^2+12^2=506.25+144=650.25,\\ \\\text{rhombus's side}=25.5\ cm.

3. The distance between the point of intersection of the diagonals and the side of the rhombus is the height of right triangle considered above.

Use twice the Pythagorean theorem to find this height:

\left\{\begin{array}{l}x^2+h^2=12^2\\(25.5-x)^2+h^2=22.5^2,\end{array}\right.

where x is projection of leg 12 cm and h is height.

Subtract the first equation from the second:

(25.5-x)^2+h^2-x^2-h^2=22.5^2-12^2,\\ \\650.25-51x=506.25-144,\\ \\51x=650.25-362.25=288,\\ \\x=\dfrac{96}{17}\ cm.

Then

h^2=144-\left(\dfrac{96}{17}\right)^2=144-\dfrac{9216}{289}=\dfrac{32400}{289},\\ \\h=\dfrac{180}{17}\ cm.

Answer: h=\dfrac{180}{17}\ cm.

7 0
3 years ago
Read 2 more answers
Is 16 an even number?​
Leni [432]

Answer:

yes

Step-by-step explanation:

cause 16 can be split into 8 unlike a odd they cant be split equal

7 0
3 years ago
Read 3 more answers
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