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Bond [772]
2 years ago
8

PLS HELP ASAP!!!!! I NEED THIS FASSTTT!!!!

Mathematics
1 answer:
Kazeer [188]2 years ago
3 0

Answer:

6?

Step-by-step explanation:

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7(x 4) can someone answer fast
jeka94
7(x+4)=0
7x+28=0
7x=-28
X=-28/7
X=-4
4 0
3 years ago
i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%
Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}

Thus, the required probability is 13.98% approximately.

Theref

7 0
1 year ago
12% of what number is 180? <br> A.<br> 15<br> B.<br> 150<br> C.<br> 1500<br> D.<br> 21.6
Doss [256]
The correct answer is C
4 0
3 years ago
Read 2 more answers
Which points are on the graph of f(x)=(1/3)^x?
frutty [35]

Answer:

(0,1)

Step-by-step explanation:

4 0
3 years ago
A set of weights includes a 5 lb barbell and 4 pairs of weight plates. Each pair of
Zina [86]

Answer:

The answer to this question would be B:

Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.

Hope this reached you well :)

Step-by-step explanation:

20 = weight of the weight plates

x = amount of weight plates.

5 = weight of the barbell

f(x) = 20(0) + 5 = 5

f(x) = 20(1) + 5 = 25

f(x) = 20(2) + 5 = 45

f(x) = 20(3) + 5 = 65

f(x) = 20(4) + 5 = 85

5 0
3 years ago
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