Answer:
(0, -3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
6x - 5y = 15
x = y + 3
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 6(y + 3) - 5y = 15
- Distribute 6: 6y + 18 - 5y = 15
- Combine like terms: y + 18 = 15
- [Subtraction Property of Equality] Subtract 18 on both sides: y = -3
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x = y + 3
- Substitute in <em>y</em>: x = -3 + 3
- Add: x = 0
Answer:
y=x,y=12x+1
y=4x+4,y=6x
y=x+1,y=x+4
Step-by-step explanation:
I am an organized person, so i make a checklist of all my notes and study them in order and that helps me a lot for the EOGs
Angle 1 = 30°
Angle 2 = 90°
⇒ Angle 3 = 60°
So, it's right triangle. We can set the length of one side and get all other sides.
So, we have 1 triangle. If there are 2 or more triangles with the same data, all the triangles will be congruent because of : <span>Two triangles are </span><span>congruent if </span>"<span>ASA: Two interior angles and the included side in a triangle have the same measure and length, respectively, as those in the other triangle</span><span>.</span>"
Hey there!!
How do we solve this problem :
We will use the combinations formula to solve this :
c ( n , r ) where n = 11 and r = 2
c ( n , r ) = n ! / r ! ( n - r ) !
... 11 ! / 2 ! ( 11 - 2 ) !
... 11! / 2! × 9!
... 11! / 2 × 9!
... 11×10×9×8×7×6×5×4×3×2 / 2×9×8×7×6×5×4×3×2
... 11×10 / 2
... 11 × 5
... 55 combinations.
Hence, the required answer = 55 , option ( d )
Hope my answer helps!
