Answer:
(ab - 6)(2ab + 5)
Step-by-step explanation:
Assuming you require the expression factorised.
2a²b² - 7ab - 30
Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term
product = 2 × - 30 = - 60 and sum = - 7
The factors are - 12 and + 5
Use these factors to split the ab- term
= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )
= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term
= (ab - 6)(2ab + 5) ← in factored form
You just put I line in the middle and you times high times base the do the other one then add your answers up that should be your finely answer
Answer:
Step-by-step explanation:
1) False: The function is decreasing (because the base, 1/3, is between 0 and 1).
2) True: The function is decreasing (see #1, above)
3) False: There is no x-intercept.
4) True: If x is 0, then y = (1/3)^0 = 1.
5) False: the range consists of the set of all real numbers greater than zero.