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2 years ago

Whats the least common denominator of 2/5 1/2 and 3/4?

Mathematics

1 answer:

Lilit [14]2 years ago

8 0

Answer:

Step-by-step explanation:

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Can I have your help

Volgvan

Answer:

3/5

Step-by-step explanation:

sin is opposite divided by the hypotenuse ( longest side)

18 is the opposite of angle x and the hypotenuse is 30

18/30 = 3/5

6 0

2 years ago

What is the value of y in the solution to this system of equations?<br> y=3-2x/2<br> 4x-6y=36

Paul [167]

Answer:

idekqwarwera

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

(-3,0),(5,-2) find the slope

Mashcka [7]

Answer:

-4

Step-by-step explanation:

Point slope form: y - y = m (x - x)

5 - (-3) = m (-2 - 0)

5 + 3 = m (-2)

8 = m (-2)

m = 8/(-2)

m=4

3 0

2 years ago

If the area of the triangular kite is 24 square ft and its base is 4 feet, find the height of the kite.

beks73 [17]

Area of a triangle is A = (1/2) (b) (h). Here we are given A and b and need to find h.

A = 24 ft^2 = (1/2) (4 ft) (height)

24 = 2(height) => height is 12 ft (answer)

3 0

3 years ago

To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and find

loris [4]

Answer:

Option D - $[0.12$

Step-by-step explanation:

Given : The manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16.

To find : The 95% confidence interval for the population standard deviation sigma?

Solution :

Number of sample n=19

The degree of freedom is Df=n-1=19-1=18

The standard deviation of the sample is s=0.16

Applying chi-square table to find critical value,

Upper critical value of $\chi^2$ is $UC=\chi(\frac{0.05}{2},18) = 31.5264$

Lower critical value of $\chi^2$ is

$LC=\chi(1-\frac{0.05}{2},18) = 8.2307$

Lower limit of the 95% confidence interval for the population variance

$L=\frac{(df)\times (s^2)}{UC}$

$L=\frac{18\times (0.16^2)}{31.5264}$

$L=\frac{18\times0.0256}{31.5264}$

$L=\frac{0.4608}{31.5264}$

$L=0.0146$

Upper limit of the 95% confidence interval for the population variance

$U=\frac{(df)\times(s^2)}{LC}$

$U=\frac{18\times (0.16^2)}{8.2307}$

$U=\frac{18\times0.0256}{8.2307}$

$U=\frac{0.4608}{8.2307}$

$U=0.0559$

So, The 95% confidence interval for the population variance is [0.0146, 0.0560]

Now, The 95% confidence interval for the population standard deviation is

$[\sqrt{0.0146}$

$[0.1208$

or $[0.12$

Therefore, Option D is correct.

The 95% confidence interval for the population standard deviation is $[0.12$

6 0

2 years ago

Whats the least common denominator of 2/5 1/2 and 3/4?​

Whats the least common denominator of 2/5 1/2 and 3/4?