Lets x = width
length = x + 4 (4 meters longer than wide)
A = L * W
192 = x ( x +4)
192 = x^2 + 4x
x^2 + 4x - 192 = 0
(x +16)(x-12) = 0
x - 12 = 0, x = 12
x + 16 = 0, x = -16
so width x = 12
length = 12 + 4 = 16 (4 meters longer than wide)
answer. J
16
Lets say that the two unknown integers are

and

.
We know the following things about

and

:


And, we want to find

.
To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

So, given what we know about the unknown integers, the previous can be written as:

We can easily solve for

:
The answer is 168.
Another approach to solve the problem is, from the two starting equations, compute the values of

and

, which are 12 and 14, and directly compute their product; however, the approach described is more elegant.
Answer:
-1/2
Step-by-step explanation:
-1/2 is the slope and -7 is the y intercept.
Answer:
150.72
Step-by-step explanation:
To find the surface area, use the provided formula and the values r = 2 and h = 10. The radius of the object is 2 since it is half the distance across the circle which measures 4 inches across through the center.
SA = 2πr² + 2πrh
SA = 2π2² + 2π(2)(10)
SA = 2π*4 + 2π(20)
SA = 8π + 40π
SA = 48π
SA = 48(3.14)
SA = 150.72
Solve in the brackets first. then the rest so...
8*{[(7+4)*2]-[(11-7)*4]} <-- this is the starting equation
8*{[(11)*2]-[(4)*4]} <-- here i solved the inner most brackets which was 7+4 and 11-7
8*{[22]-[16]} <-- then i multiplied 11 by 2 to get 22 and 4 by 4 to get 16
8*{6} <-- here i subtracted 16 from 22 to get 6
48 < and then the answer which i got by multiplying 6 and 8
**note: keep BEDMAS/BODMAS in your mind. u solve the inner most brackets first and then you move outside.
48 is the answer
hope it helped :)