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julia-pushkina [17]
3 years ago
5

Plzzz helpppp333332222222222

Mathematics
2 answers:
yan [13]3 years ago
8 0

Answer:

B. 10 units

Step-by-step explanation:

Use the pythagorean theorem. (a^2 + b^2 = c^2)

Pretend that PQ is the hypotenuse of a right triangle.

Count the number of units for the supposed legs of the triangle.

The height would be 6 while the base is 8.

6^2 + 8^2 = PQ^2

36 + 64 = PQ^2

100 = PQ^2

PQ = 10

So, the answer is B.

Sati [7]3 years ago
5 0

Answer: The answer is C or 13 units

How?: by a method called rise over run

the rise is at the y axis and the run is at x axis

*COUNT VERY CAREFULLY*

if you count right you should get 6 as a rise and  7 for run

6+7= 13

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2+3x7-32x64-8+764x33398x986+12
Serggg [28]

2+3x7-32x64-8+764x33398x986+12=

25158844971

4 0
3 years ago
A recipe needs 4/5 cup of butter for every 2 cups of flour. If you plan to use 3 cups of flour, how much butter will you need?
tatuchka [14]

Answer:

Step-by-step explanation:

2.4 cups

5 0
3 years ago
Which solid figures do NOT have a vertex or vertices? (Check all that apply.)
Hatshy [7]
I would go with cylinders cause it's a tube it doesn't any sharp points or angles like the other choices. hope this helps.
8 0
3 years ago
Read 2 more answers
Solve the solution using the substitution method <br><br>3x +5y = 29<br>y= -4x -1
Artist 52 [7]
3x + 5y = 29         first equation
y = -4x - 1             second equation

substitute the second equation to the first equation;
3x + 5(-4x - 1) = 29
-17x - 5 = 29

solve for x;
-17x - 5 = 29
-17x = 34
x = -2

substitute x = -2 into the second equation to find y;
y = -4x - 1
y = -4(-2) - 1
y = 8 - 1
y = 7

so;
x = -2,  y = 7

hope this helps, God bless!
3 0
3 years ago
What is the exact value of sin(105°)?<br><br><br>ANSWER - D) sqrt(2 + sqrt3)/2
Fofino [41]

Answer:

\sin 105^{\circ} = \frac{\sqrt{6}+\sqrt {2}}{4}

Step-by-step explanation:

We can use the following trigonometrical identity:

\sin (\alpha - \beta) = \sin \alpha \cdot \cos \beta - \cos \alpha \cdot \sin \beta (1)

Where \alpha, \beta are angles, measured in sexagesimal degrees.

If we know that \alpha = 135^{\circ} and \beta = 30^{\circ}, then the value of the given function is:

\sin 105^{\circ} = \sin 135^{\circ}\cdot \cos 30^{\circ} - \cos 135^{\circ}\cdot \sin 30^{\circ}

\sin 105^{\circ} = \left(\frac{\sqrt{2}}{2} \right)\cdot \left(\frac{\sqrt{3}}{2}\right)-\left(-\frac{\sqrt{2}}{2} \right)\cdot \left(\frac{1}{2}\right)

\sin 105^{\circ} = \frac{\sqrt{6}}{4}+\frac{\sqrt{2}}{4}

\sin 105^{\circ} = \sqrt{\frac{6}{16} }+\sqrt{\frac{2}{16} }

\sin 105^{\circ} = \sqrt{\frac{3}{8} }+\sqrt{\frac{1}{8} }

\sin 105^{\circ} = \frac{\sqrt{3}+1}{2\cdot \sqrt{2}}

\sin 105^{\circ} = \frac{\sqrt{6}+\sqrt {2}}{4}

7 0
3 years ago
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