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eduard
3 years ago
9

Susan has 10 pockets and 44 dollar bills. She wants to arrange the money so that there are a different number of dollars in each

pocket. Can she do it? Explain.
Mathematics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

No

Step-by-step explanation:

The answer is no because no pocket can be empty and there isn't enough money to satisfy the condition. At least, one dollar must be stored in each pocket but the number (integer) of dollars in each pocket is different.

Let's store the minimum amount of dollars in the pockets while satisfying the condition. Place 1 dollar in the first pocket. The second pocket must have 2 dollars (it can't be 1 dollar, it must be a different number of dollars). The third pocket must have third dollars.

Repeating this process, the ninth pocket must have 9 dollars. At this moment, we have arranged 1+2+3+4+5+6+7+8+9=45 dollars in our pockets. But we only had 44 dollars! Plus, the tenth pocket is still empty.

If you store more dollars on the first, second, nth pockets, you will just run out of money more quickly than in our process above. so it's impossible to arrange the money in such way.

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11111nata11111 [884]

2x(3×2 – 2x – 8)

6 \times 3 - 4 \times 2 - 16x

6(3 - 4 \times 2 - 16x)

2x(3 \times 2 - 2x - 8)

7 0
3 years ago
Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius r. width units height units
dmitriy555 [2]

This question is incomplete, the remaining part of the question is upload as an image alongside this answer.

Answer:

Width = 2x = 2( r/√2 ) =  √2 r units

Height = 2y = 2( r/√2 ) =  √2 r units

Step-by-step explanation:

From the Figure on the image; lets consider the circle of radius r, centered at the origin.  

let ABCD be the largest rectangle that can be inscribed inside the circle.  

Let the half width of the rectangle be x, then in right triangle ONB using Pythagorean theorem,  

half height of rectangle y = √(r² - x²)

Thus the width of the inscribed rectangle = 2x and height of the inscribed rectangle = 2√(r² - x²)

thus the area of the inscribed rectangle = length × width

⇒ A(x) = 2x(2√(r² - x²))

⇒ A(x) = 4x√(r² - x²)  

now in order to maximize the area, we find critical points.

so we find the derivative and set that zero, that is Ai(x) = 0.

so using product rule, we get

A'(x) = 4x × ( -2x / 2√(r² - x²) ) + ( 4 × √(r² - x²)  )

A'(x) = ( -4x² / √(r² - x²) ) + ( 4√(r² - x²)  )

Now for critical points, set A'(x) = 0

so

( -4x² / √(r² - x²) ) + ( 4√(r² - x²)  ) = 0

( 4x² / √(r² - x²) ) =  ( 4√(r² - x²)  )

x² = r² - x²

2x² = r²

x² = r²/2

x = ±√(r²/2)

Now since x represent the with, it cannot be negative, Thus

x = r/√2

hence

y = √(r² - x²) = √(r² -  r²/2) = √(r²/2) =  r/√2

Therefore, the dimensions of the rectangle of largest area will be;

Width = 2x = 2( r/√2 ) =  √2 r units

Height = 2y = 2( r/√2 ) =  √2 r units

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gayaneshka [121]

Answer:

w = -\frac{9}{8}

Step-by-step explanation:

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We can first use distributive property to simplify, the distributive property is  a(b+c)=ab+ac

Thus we have:

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Speed can be defined as the distance covered by a physical object per unit of time. Thus, the cyclist's speed can be measured as miles per minutes.

Mathematically, speed is given by this formula;

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Substituting the given parameters into the formula, we have;

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Read more on speed here: brainly.com/question/10545161

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