Ask question

Ask question

All categories

3 years ago

9

A a rectangular parking lot has a length that is 15 yards greater than the width. the area of the parking lot is 450 square yard

s find the length and the width

1 answer:

Lelu [443]3 years ago

6 0

The numbers are 30 and 15. Length is 15 and width is 30.

You might be interested in

What are the pattern conbination between these number 18 48 88 128 178 38 68

valentina_108 [34]

18+30=48
48+40=88
88+40=128
128+50=178

Thats all i found so far in the pattern
30,40,40,50
then it drops
by 140 then adds by 30..

I dont know how else to explain it

7 0

3 years ago

Help asap please:<br><br> Solve x-7y=16 for y

Pepsi [2]

Answer:

y = (x-16)/7

Step-by-step explanation:

x - 7y = 16

~Subtract x to both sides

-7y = 16 - x

~Divide -7 to everything

y = (16-x)/7

Best of Luck!

5 0

3 years ago

Read 2 more answers

F (-2)=x+6. evaluate the function

damaskus [11]

X= -8 that uis your answer for that question :)

8 0

3 years ago

Read 2 more answers

Photo above <br><br>please answer

alina1380 [7]

I THINK the answer would be around 2/3/4 paper clips, I'm not sure. And keep in mind, I;m not responsible for any wrong answers/ invalid responses.

5 0

4 years ago

Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu

Alona [7]

Answer:

We have the equation

$c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]$

Then, the augmented matrix of the system is

$\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]$

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

$\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]$

This matrix is in echelon form. Then, now we apply backward substitution:

1.

$8c_4=0\\c_4=0$

2.

$4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0$

3.

$3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0$

4.

$c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0$

Then the system has unique solution that is $(c_1,c_2c_3,c_4)=(0,0,0,0)$ and this imply that the vectors $v_1,v_2,v_3,v_4$ are linear independent.

4 0

3 years ago