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bezimeni [28]
3 years ago
11

Enter the opposite of 4/5 and − 7/15.

Mathematics
2 answers:
makkiz [27]3 years ago
5 0

Answer:

1/3

Step-by-step explanation:

Nady [450]3 years ago
4 0
The answers are: 5/4 and -15/7

To find the opposite just switch the numerator with the denominator!
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Find the midpoint of segment EF if E (5,-2) F(1,-8) URGENT
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Answer

(3, -5)

Step-by-step explanation:

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Step-by-step explanation:

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Paul is going to have the exterior of his home painted. Painting USA charges $75.00 to come out and evaluate the house plus $25.
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In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0
3 years ago
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s. a. Substitute the values into the ver
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I think it'd be 9 seconds, not 100% sure though.
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