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Answer:
a)This solution matches with the original equation and its solution
b)This solution matches with the original equation and its solution
c)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
d)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
Step-by-step explanation:
i) Which scenarios can be solved by 1.5x + 2.25 = 12.75. Select all that apply and note the given solution.
therefore 1.5x = 10.5 therefore x = 7
a) let the number be x
therefore if then the number x = 7.
This solution matches with the original equation and its solution
b.) If a taxi driver charges a flat fee of $2.25 and $1.5 per mile, where the
number of mile = x, then the number of miles Juan can ride the taxi for
$12.75 is x = 7.
This solution matches with the original equation and its solution
c)if nine quarters of a number, say x, increased by three halves is fifty one
quarters, the number is x = 5,
This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
d.) If a taxi driver charges a flat fee of $1.5 and $2.25 per mile, where the
number of mile = x, then the number of miles Juan can ride the taxi for
$12.75 is x = 5.
This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
Answer:
We would have
where " l " is length, " w" is width and "h" is height.
Step-by-step explanation:
Step 1
Remember that
Surface area for a box with no top =
where " l " is length, " w" is width and "h" is height.
Step 2.
Remember as well that
Volume of the box =
Step 3
We can now use lagrange multipliers. Lets say,
and
By the lagrange multipliers method we know that
Step 4
Remember that
and
So basically you will have the system of equations
Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get
Then you would get
You can get rid of from these equations and you would get
And from those equations you would get
Now remember the original equation
If we plug in what we just got, we would have