60/100 we not read by the third and fifth grade
What picture ? Did you attached it
//5^-3 = 1/(5^3)
(2^2*5^6)/(5^3*2^3*5^2)=
(2^2*2^-3)*(5^6*5^-3*5^-2)=
(2^-1)*(5^1)=
5/2=
2.5=
Answer:
x=21
Step-by-step explanation:
Following the vertical angles, we can assume that the equation that has x and 87 are equal to each other. From then, you set them equal to each other and solve for x.
87=4x+3
84=4x subtract 3 from both sides
21=x divide by 4 to get the x alone on both sides
lets start by labeling the rectangle. let w = width so length(l) = w+4 (i.e 4 more than the width)
Perimeter of a rectangle= sum of all the sides= l+ w+l+w=2l +2w
now we know that p = 2l + 2w = 100
but we know that l=w+ 4
so
2(w+4) +2w=100
2w +8 +2w = 100
4w+8 =100
4w= 92
w=23
and if we substitute into 2l+2w= 100
we will get l =27.
