WOULD U RATHER?? Please show your work Which one would u choose?

The area of a trapezoid is found using the formula A=1/2h(b^1+b^2), where b^1 and b^2 are the parallel sides of the trapezoid an

OverLord2011 [107]

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{1}{2}h(b_1+b_2)~~ \begin{cases} A=18\\ b_1=5\\ b_2=7 \end{cases}\implies 18=\cfrac{1}{2}h(5+7) \\\\\\ 18=\cfrac{h(12)}{2}\implies 18=6h\implies \cfrac{18}{6}=h\implies 3=h$

3 0

3 years ago

Which expression could be used to determine the reduction of -4 and 3 1/4

Setler79 [48]

Answer:

The expression that could be used is (-4)(3) + (-4)( $\frac{1}{4}$ ) ⇒ B

Step-by-step explanation:

Let us revise the distributive property:

The product of a number and the sum of 2 other numbers equal to the sum of the products of the number with the other 2 numbers

a(b + c) = ab + ac

We will use this rule to solve the question

∵ The product of -4 and 3 $\frac{1}{4}$ = -4 × 3 $\frac{1}{4}$

→ We can right 3 $\frac{1}{4}$ as (3 + $\frac{1}{4}$ )

∵ 3 $\frac{1}{4}$ = (3 + $\frac{1}{4}$ )

∴ -4 × 3 $\frac{1}{4}$ = -4(3 + $\frac{1}{4}$ )

→ By using the rule above

∵ -4(3 + $\frac{1}{4}$ ) = (-4)(3) + (-4)( $\frac{1}{4}$ )

∴ -4 × 3 $\frac{1}{4}$ = (-4)(3) + (-4)( $\frac{1}{4}$ )

∴ The expression that could be used is (-4)(3) + (-4)( $\frac{1}{4}$ )

3 0

3 years ago

Multiplied by 3/4 and then divided by 3/5 is the same as dividing by what?

netineya [11]

We have: x × $\frac{3}{4}$ ÷ $\frac{3}{5}$ = x × $\frac{3}{4}$ × $\frac{5}{3}$ = x × $\frac{5}{4}$ = x ÷ $\frac{4}{5}$

ANSWER: E. 4/5

Ok done. Thank to me :>

6 0

3 years ago

To decrease the impact on the environment, factory chimneys must be high enough to allow pollutants to dissipate over a larger a

Komok [63]

Answer:

The probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

Step-by-step explanation:

Let the random variable X be defined as the height of chimneys in factories.

The mean height is, μ = 100 meters.

The standard deviation of heights is, σ = 12 meters.

It is provided that a random sample of n = 40 chimney heights is obtained.

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

Since the sample selected is quite large, i.e. n = 40 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean heights of chimneys.

$\bar X\sim N(\mu_{\bar x},\ \sigma^{2}_{\bar x})$

Compute the probability hat the sample mean height for the 40 chimneys is greater than 102 meters as follows:

$P(\bar X>102)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}})>\frac{102-100}{12/\sqrt{40}})$

$=P(Z>1.05)\\=1-P(Z$

*Use a z-table fr the probability.

Thus, the probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

8 0

3 years ago

Helpppppppppppppppppppppppppppppp

White raven [17]

My graphing calculator says g(4) = f(2).

The 4th selection, x=4, is appropriate.

8 0

3 years ago

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